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GalinKa [24]
3 years ago
8

What is the formula for the system of equation usign the substitution?

Mathematics
1 answer:
olga_2 [115]3 years ago
7 0
We can substitute<span> y in the second </span>equation<span> with the first </span>equation<span> since y = y. The solution of the </span>linear<span> system is (1, 6). You can use the </span>substitution method<span> even if both </span>equations<span> of the </span>linear<span> system are in standard form. Just begin by solving one of the </span>equations<span> for one of its variables.</span>
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Answer:

t=\frac{85.8-113.4}{\sqrt{\frac{(50)^2}{145}+\frac{(75)^2}{141}}}}=-3.65  

p_v =2*P(t_{(284)}

Using Excel we can use the following code: "=2*T.DIST(-3.65;284;TRUE)"

So the p value is a very low value and using any significance level giveen \alpha=0.05 always p_v so we can conclude that we have enough evidence to reject the null hypothesis, and there is enough evidence to conclude that the means are different.

Step-by-step explanation:

1) Data given and notation

\bar X_{M}=85.8 represent the mean for the males

\bar X_{F}=113.4 represent the mean for females

s_{M}=50 represent the sample standard deviation for males

s_{F}=75 represent the sample standard deviation for female

n_{M}=145 sample size for the group poisoned

n_{F}=141 sample size for the group unpoisoned

t would represent the statistic (variable of interest)

2) Concepts and formulas to use

We need to conduct a hypothesis in order to check if the mean for the two groups are equal or not , the system of hypothesis would be:

Null hypothesis:\mu_{M} = \mu_{F}

Alternative hypothesis:\mu_{M} \neq \mu_{F}

If we analyze the size for the samples both are higher than 30 but the population deviations are not given, so for this case is better apply a t test to compare means, and the statistic is given by:

t=\frac{\bar X_{M}-\bar X_{F}}{\sqrt{\frac{s^2_{M}}{n_{M}}+\frac{s^2_{F}}{n_{F}}}} (1)

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

3) Calculate the statistic

We can replace in formula (1) the results obtained like this:

t=\frac{85.8-113.4}{\sqrt{\frac{(50)^2}{145}+\frac{(75)^2}{141}}}}=-3.65  

4) Statistical decision

The first step is calculate the degrees of freedom, on this case:

df=n_{M}+n_{F}-2=145+141-2=284

Since is a two tailed test the p value would be:

p_v =2*P(t_{(284)}

Using Excel we can use the following code: "=2*T.DIST(-3.65;284;TRUE)"

So the p value is a very low value and using any significance level giveen \alpha=0.05 always p_v so we can conclude that we have enough evidence to reject the null hypothesis, and there is enough evidence to conclude that the means are different.

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Answer:

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