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3 years ago

(25 points) Can someone please solve this I just need to see how its solved to understand

Mathematics

1 answer:

aleksley [76]3 years ago

4 0

x = total amount of students in 8th Grade.

we know only one-thrid of the class went, so (1/3)x or x/3 went.

we also know 5 coaches went too, and that the total amount of that is 41.

$\bf \stackrel{\textit{one third of all students}}{\cfrac{1}{3}x}+\stackrel{\textit{coaches}}{5}=\stackrel{\textit{total}}{41}\implies \cfrac{x}{3}+5=41\implies \cfrac{x}{3}=41-5 \\\\\\ \cfrac{x}{3}=36\implies x=3(36)\implies x=108$

now, to verify, well, what do you get for (108/3) + 5?

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Solve for x:

Anna71 [15]

Answer:

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2 years ago

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In a horse race with 5 horses, you make a bet by predicting the ranking of all 5 horses. Suppose you place your bet at random. W

lapo4ka [179]

Answer:

P( top two horses are predicted incorrectly in incorrect order)

= $\frac{1}{2}$

Step-by-step explanation:

In the horse race the outcome can be predicted in 5! = 120 ways.

Now suppose the top two horses were predicted incorrectly in incorrect order. Now, the top horse can be predicted incorrectly in 4 ways.

Suppose the top horse was predicted to be in k-th position where k = 2, 3 ,4,5

so the second horse can be predicted to be in place from 1 to (k - 1)

So, the top two horses can be predicted incorrectly in incorrect order

in $\sum_{k =2}^{5}(k - 1)$ = 10 ways

and for each prediction of the two the remaining horses may be predicted in 3! = 6 ways.

Hence ,

P( top two horses are predicted incorrectly in incorrect order)

= $\frac{6 \times 10}{120}$

= $\frac{1}{2}$

8 0

2 years ago

Please helppp

tangare [24]

Answer:

Adult: 50 tickets

Child: 34 tickets

Step-by-step explanation:

Let a be the amount of adult tickets

Let c be the amount of child tickets

Equation:

a + c = 84

14a + 9c = 1,006

Step 1: Multiply a + c = 84 with -9, to canceled c.

-9 (a + c = 84) → -9a - 9c = -756

14a + 9c = 1006 → 14a + 9c = 1006

Step 2: Combined the 2 equation together, and solved it.

-9a - 9c = -756

14a + 9c = 1006

5a = 250

5 5

a = 50

Step 3: Plug 50 into the one of the equation, and solved it.

a + c = 84 → 50 + c = 84

-50 -50

c = 34

Answer: Adult tickets (a) = 50 and Child tickets (c) = 34

To check the answer plug the two number into the equation ( Make sure to add 50 for a and 34 for c).

3 0

3 years ago

Teresa bought 3boxes of chocolate each box has 9 pieces of chocolate inside teresa gave away 15 pieces of chocolate how many pie

lora16 [44]

Hey There!

3×9=27
27-15=12
Teresa has 12 pieces of Chocolate left

Hope This Helps!!!!

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3 years ago

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Yuto and Riko went for a bike ride on the same path. When Riko left their house, Yuto was 5.25 miles along the path. If Yuto’s a

Nimfa-mama [501]

Answer:

Step-by-step explanation:

When Riko left his house, Yuto was 5.25 miles along the path.

Average speed of Riko = 0.35 miles per minute

Average speed of Yuto = 0.25 miles per minute

First we will calculate the time in which Riko will catch Yuto on the track.

Relative velocity of Riko as compared to Yuto will be = velocity of Riko - velocity of Yuto

= 0.35 - 0.25

= 0.10 miles per minute

Now we this relative velocity tells that Riko is moving and Yuto is in static position.

By the formula,

Average speed = $\frac{Distance}{Time}$

0.10 = $\frac{5.25}{t}$

t = $\frac{5.25}{0.1}$

t = 52.5 minutes

Now we know that Rico will catch Yuto in 52.5 minutes. Before this time he will be behind Yuto.

So duration of time in which Rico is behind Yuto will be 0 ≤ t ≤ 52.5

Here time can not be less than zero because time can not be with negative notation. It will always start from 0.

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3 years ago

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