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Lera25 [3.4K]
3 years ago
13

Is 21 to the square root of 2 rational or irrational

Mathematics
1 answer:
Step2247 [10]3 years ago
3 0
It is equal to 21/2 which is a rational number
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Which type of human body cell would you except to have the most amount of folding in the mitochondria? A. Appendix B. Liver C. H
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C. Heart

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4 years ago
A 1.5 m tall woman stands next to the Eiffel Tower. At this time of day, her shadow is 0.5 m long. At the same time, the tower's
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270m, Since .5 is a third of the women’s height the 90m of the Eiffel Tower you multiply by 3 to get the original height
7 0
3 years ago
Don't really understand this
Fofino [41]

Answer:

24 units²

Step-by-step explanation:

In this polygon to find the area you have to split it into 2 shapes. In this case, splitting it into a quadrilateral and a triangle makes the most sense. Let's find the area of the rectangle first. To do that, count the amount of units on the base and height and multiply them. In this case, that would be 4×5 so 20u². Now we have to find the triangle area. We see that the triangle has a right triangle so the formula would be base*height/2. In the picture, we can see that the base is 2 and the height is 4 so we would do 4×2 (8) divided by 2 to get 4u². Now add the rectangle and triangle height to get an answer of 24u² for the area.

6 0
3 years ago
What are the solving steps and two
Pepsi [2]

Answer:

-x² - 10x -21 = 0

x² +10x +21 = 0

x² + 7x + 3x + 21 = 0

x ( x+7) + 3 (x+7) = 0

(x+3) (x+7) = 0

when (x+3) = 0,

   x = -3

Again,

(x+7) = 0

x = -7

5 0
2 years ago
Read 2 more answers
Y=3x-5<br> 2y - 3x = 5 <br> Solve by subsitution
m_a_m_a [10]
\left\{\begin{array}{ccc}y=3x-5\\2y-3x=5\end{array}\right\\\\substitute\ y=3x-5\ to\ 2y-3x=5\\\\2(3x-5)-3x=5\\2\cdot3x-2\cdot5-3x=5\\6x-10-3x=5\\3x-10=5\ \ \ /+10\\3x=15\ \ \ \ /:3\\x=5\\\\

\left\{\begin{array}{ccc}x=5\\y=3x-5\end{array}\right\\\left\{\begin{array}{ccc}x=5\\y=3\cdot5-5\end{array}\right\\\left\{\begin{array}{ccc}x=5\\y=15-5\end{array}\right\\\left\{\begin{array}{ccc}x=5\\y=10\end{array}\right
6 0
3 years ago
Read 2 more answers
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