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Volgvan
3 years ago
5

Help please

Mathematics
2 answers:
Firdavs [7]3 years ago
8 0

Answer: THE ANSWER IS R(x)=9x+69

Step-by-step explanation:

Elza [17]3 years ago
8 0

Answer:

R(x)= 20x^2+300x+1080

Step-by-step explanation:

The number of teams who entered in  basketball tournament

T(x)=4x+24

The entire fee paid by each team to enter the tournament

F(x)=5x+45

Total entry fees = Number of teams * fee paid by each term

R(x)= T(x) * F(x)

R(x)= (4x+24) *(5x+45)

USe FOIL method to multiply it

R(x)= 20x^2+180x+120x+1080

combine like terms

R(x)= 20x^2+300x+1080

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2 years ago
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5 0
3 years ago
Ms. Nina has 10 lbs of 25% sugar syrup. How much water does she need to add to make 10% sugar syrup?
ryzh [129]
She has 10lbs of 25% syrup... so, in the 10lbs, 25% of that is syrup, the rest, namely the 75% remaining is water or other substances.

let's say she adds "x" lbs of water, to get "y" lbs for the 10% mixture.

how much is 25% of 10lbs?  well, (25/100) * 10, or 2.5.

the water has no sugar syrup in it, so is just pure water, so the amoun of syrup in it is 0%, how much is 0% of "x" lbs?  well, (0/100) * x, or 0.00x, which is just 0.

how much is 10% of "y" lbs?  well (10/100) * y, or 0.10y.

whatever "x" and "y" are, we know that 10 + x = y.

we also know that the syrup amount in that is also 2.5 + 0.00x = 0.10y, thus


\bf \begin{array}{lccclll}
&\stackrel{lbs}{syrup}&\stackrel{concentration~\%}{syrup}&\stackrel{concentration}{amount}\\
&------&------&------\\
\textit{25\% syrup}&10&0.25&2.5\\
\textit{pur water}&x&0.00&0.00x\\
------&------&------&------\\
\textit{10\% mixture}&y&0.10&0.10y
\end{array}
\\\\\\
\begin{cases}
10+x=\boxed{y}\\
2.5+0.00x=0.10y\\
----------\\
2.5 = 0.10\left( \boxed{10+x} \right)
\end{cases}
\\\\\\
2.5=1 + 0.10x\implies 1.5=0.10x
\\\\\\
\cfrac{1.5}{0.10}=x\implies 15=x
8 0
3 years ago
Read 2 more answers
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