Answer:
58 units squared
Step-by-step explanation:
We want to find the area of the square. To do so, we need to find the hypotenuse of the right triangle because this coincides with the side length of the square.
We use the Pythagorean Theorem, which states that for a right triangle with legs a and b and hypotenuse c:
a^2 + b^2 = c^2
Here, a = 7 and b = 3, so:
7^2 + 3^2 = c^2
c^2 = 49 + 9 = 58
Now, the area of a square is: A = s^2, where s is the side length. Well, c is the side length, and we've already found what c^2 is (it's 58), so that means the area of the square is 58 units squared.
Thus, the answer is 58 units squared.
Step-by-step explanation:
17.0 there you go I hope this helped
since LM=LN there values are same which is given as 5.5 cm and MN =7cm
now draw a line LM which is 5.5 cm long. From one point of this line construct an arc 5.5 cm in upward direction.Then from the opposite end of the same line LM construct an arc 7 cm long in upward direction. Let it meet the the first arc at any point. The arcs will meet for sure at any angle. Join the two ends of line LN to this point where they meet. We get a triangle!
Remember to mark LM , LN and MN as soon as u draw them so as to avoid confusion.
<em>IF U WANT I'LL DO IT AND SEND A PHOTO</em>
Answer:
5
Step-by-step explanation:
The interquartile range is the difference between the upper quartile and the lower quartile.
First find the median.
The median is the middle value of the data set arranged in ascending order
1 5 5 7 9 ← data in ascending order
↑ median
The lower quartile is the middle value of the data to the left of the median. If there is not an exact middle then it the average of the values on either side of the middle.
1 5
↑ lower quartile = 
= 3
The upper quartile is the middle value of the data to the right of the median.
7 9
↑ upper quartile = 
= 8
Thus
interquartile range = 8 - 3 = 5
