Which rule represents the translation from the pre-image, ΔABC, to the image, ΔA'B'C'?

Mathematics

2 answers:

V125BC [204]3 years ago

8 0

Answer:

(x, y) → (x + 7, y – 6).

Step-by-step explanation:

ANEK [815]3 years ago

6 0

From the figure, it can be seen that the mage A'B'C' is obtained from the pre-image ABC by translating/shifting the vertices of the image by 7 units to the right and 6 units down.

Therefore, the rule represents the translation from the pre-image, ΔABC, to the image, ΔA'B'C' is (x, y) → (x + 7, y – 6).

You might be interested in

I’m confused on this one

Alenkinab [10]

Remark

I would have had the answer a whole lot sooner if I would have read the question properly. The figure in the circle is called a cyclic quadrilateral. It has the odd property that the angles that are opposite each other add up to 180o.

So DEB + DCB = 180o

DEB = 180 - 87

DEB = 93o

Note: The arcs marked 60 and 76 have nothing whatever to do with this problem.

7 0

2 years ago

"a man drove 10 mi directly east from his home, made a left turn at an intersection, and then traveled 5 mi north to his place o

Mariulka [41]

Answer:

11.2 miles

Step-by-step explanation:

We can create a triangle from the information given.