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Yanka [14]
3 years ago
13

60 percent of what is 181

Mathematics
1 answer:
dangina [55]3 years ago
4 0
181(0.60)=108.6 or 543/5
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If (3a-5b) : (3a+5b)=1:4 then find the value of a:b​
rodikova [14]

Answer:

a : b = 25 : 9

Step-by-step explanation:

(3a - 5b) : (3a + 5b) = 1 : 4

Product of extremes = product  of  means

(3a - 5b) *4 = (3a +5b) * 1    {Distributive property}

3a * 4  - 5b*4 = 3a + 5b

12a - 20b = 3a + 5b

Add 20b to both sides

12a = 3a + 5b + 20b

12a = 3a + 25b

Subtract 3a from both sides

12a - 3a = 25b

9a = 25b

\dfrac{a}{b}=\dfrac{25}{9}

a:b = 25 : 9

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3 years ago
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Step-by-step explanation:

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6 0
3 years ago
In MON, J, K, and L are midpoints. If JL = 11, LK = 13, and ON = 20, and JL || MN, LK || MO, and JK || ON, what is the length of
In-s [12.5K]

Answer:

The lengths of MN is 22 units, MO is 26 units and JK is 10 units

Step-by-step explanation:

<em>A l</em><em>ine segment</em><em> joining the </em><em>mid-points of two sides</em><em> in a triangle is </em><em>parallel to the third side</em><em> and </em><em>equal to half its length</em>

In Δ MON

∵ J, K, and L are mid-points

∵ JL // MN and LK // MO

∴ L is the mid-point of ON

∴ J is the mid-point of MO

∴ K is the mid-point of MN

∵ J, L are the mid-points of MO and ON

∵ JL is opposite to MN

→ By using the rule above

∴ JL = \frac{1}{2} MN

∵ JL = 11 units

∴ 11 = \frac{1}{2} MN

→ Multiply both sides by 2

∴ 22 = MN

∴ MN = 22 units

∵ K, L are the mid-points of MN and ON

∵ KL is opposite to MO

→ By using the rule above

∴ KL = \frac{1}{2} MO

∵ KL = 13 units

∴ 13 = \frac{1}{2} MO

→ Multiply both sides by 2

∴ 26 = MO

∴ MO = 26 units

∵ J, K are the mid-points of MO and MN

∵ JK is opposite to ON

→ By using the rule above

∴ JK = \frac{1}{2} ON

∵ ON =20 units

∴ JK = \frac{1}{2} (20)

∴ JK = 10 units

∴ The lengths of MN are 22 units, MO is 26 units and JK is 10 units

3 0
3 years ago
The diameter of a circle measures 20 yd. What is the circumference of the circle?
Pani-rosa [81]

Answer: 62.8 yd

Step-by-step explanation:

Circumference= diameter*pi

20*3.14= 62.8

5 0
3 years ago
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