1 real zero is the answer
Answer:
Minimum at (-4, -10)
Step-by-step explanation:
x² + 8x + 6
The coefficient of x² is positive, so the parabola opens upward, and the vertex is a minimum.
Subtract the constant from each side
x² + 8x = -6
Square half the coefficient of x
(8/2)² = 4² = 16
Add it to each side of the equation
x² + 8x + 16 = 10
Write the left-hand side as the square of a binomial
(x + 4)² = 10
Subtract 10 from each side of the equation
(x+ 4)² -10 = 0
This is the vertex form of the parabola:
(x - h)² + k = 0,
where (h, k) is the vertex.
h = -4 and k = -10, so the vertex is at (-4, -10).
The Figure below shows your parabola with a minimum at (-4, -10).
Answer:
-25x⁵y⁵
Step-by-step explanation:
Coefficients include (-5)(5) = -25
x-factors include (x^3)(x^2) = x^5
y-factors include (y^2)(y^3) = y^5
Then the product is ...
... -25x^5·y^5
SOLUTION:
From the figure, all 4 angles are congruent. Since each pair of opposite angles are congruent, the quadrilateral is a parallelogram by Theorem 6.10.
Answer:
translate the road down 4 units
Hope this helps