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Naddika [18.5K]
3 years ago
9

How many extraneous solutions are there ?

Mathematics
2 answers:
Arte-miy333 [17]3 years ago
8 0

Answer:

its 0 i put 2 the first time but it was wrong:{} its 0 tho

Step-by-step explanation:

vfiekz [6]3 years ago
6 0
2 is your correct answer
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Which of the following numbers is not written in scientific notation?
Sonja [21]

Answer A

Step-by-step explanation:

Because there is a zero at the begining.

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3 years ago
The graph of the derivative of a function f crosses the x-axis 3 times. What does this tell you about the graph of f ?
expeople1 [14]

Answer:

D. The function f has 3 horizontal tangent lines

Step-by-step explanation:

Well whenever any function crosses the x-axis, it means that the y-value is equal to zero.

In this case when the derivative passes the x-axis it indicates the tangent line corresponding to that x-value has a slope of zero, which when plotted is a horizontal line.

This means that the graph f has 3 horizontal tangent lines.

7 0
1 year ago
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What is the sum of 5.3 x 10^5 and 3.8 x 10^4in scientific notation?
Natali5045456 [20]

Answer:

=5.68×10^5

Step-by-step explanation:

7 0
3 years ago
FIRST CORRECT ANSWER GETS BRAINLIEST AND 50 POINTS.
AnnyKZ [126]

Answer:

A) 5^3*5^{-4}=5^{3-4}=5^{-1}=\frac{1}{5} (Yes. It has a value between zero and one.)

B) \frac{3^5}{3^{-6}}=3^{5-\left(-6\right)}=3^{5+6}=3^{11}=177147 (No. It does not have a value between zero and one.)

C) \left(\frac{1}{4}\right)^3* \left(\frac{1}{4}\right)^2=\left(\frac{1}{4}\right)^{3+2}=\left(\frac{1}{4}\right)^5=\frac{1^5}{4^5}=\frac{1}{1024}. (Yes. It has a value between zero and one.)

D) \frac{\left(-7\right)^5}{\left(-7\right)^7}=\left(-7\right)^{5-7}=\left(-7\right)^{-2}=\frac{1}{\left(-7\right)^2}=\frac{1}{49} (Yes. It has a value between zero and one.)

4 0
3 years ago
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If f(x) = -x + 8 and g(x) = x^4, what is (gºf)(2)?
kotykmax [81]

Answer:

\large\boxed{(g\circ f)(2)=1296}

Step-by-step explanation:

(g\circ f)(x)=g\bigg(f(x)\bigg)\\\\f(x)=-x+8,\ g(x)=x^4\\\\(g\circ f)(x)=\g\bigg(f(x)\bigg)=(-x+8)^4\\\\(g\circ f)(2)\to\text{put x = 2 to the equation}\ (g\circ f)(x):\\\\(g\circ f)(2)=(-2+8)^4=(6)^4=1296

7 0
3 years ago
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