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2 years ago

Which is the volume of the solid?

Mathematics

2 answers:

shepuryov [24]2 years ago

3 0

Answer: the answer is A

Step-by-step explanation:

stich3 [128]2 years ago

3 0

ANSWER:

As we can see in figure, the above solid is only made from cubes.

So, volume = No of cubes in it.

Therefore, Volume of above solid = 14 cubic units.

So, Correct choice - [A] 14 cubic units.

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A triangle can be formed with side lengths 3 in, 5 in, and 9 in. True or False?

Lelechka [254]

Answer:

no this cant form a right triangle but can form a regular triangle

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Help with number 22. Image above.

stellarik [79]

I think the answer to this question is letter A

3 0

3 years ago

Big Mack buys meat for the family reunion cookout. He needs to buy 11 packagesof meat. A package of hotdogs costs $2.59, and a p

IgorC [24]

Hello!

Let's write some important information contained in the exercise:

• hotdogs: $2.59 (,x,)

• hamburgers: $5.29 (,y,)

He needs 11 packages. Let's write it:

• x + y = 11

He spent a total of $39.29. We can write it as:

• 2.59x + 5.29y = 39.29

Now, let's solve these two equations as a linear system:

$\begin{cases}x+y=11\text{ equation A} \\ 2.59x+5.29y=39.29\text{ equation B}\end{cases}$

First, let's isolate x in equation A:

$\begin{gathered} x+y=11 \\ x=11-y \end{gathered}$

Now, we will replace where's x by 11-y in equation B:

$\begin{gathered} 2.59x+5.29y=39.29 \\ 2.59(11-y)+5.29y=39.29 \\ 28.49-2.59y+5.29y=39.29 \\ -2.59y+5.29y=39.29-28.49 \\ 2.7y=10.8 \\ y=\frac{10.8}{2.7} \\ \\ y=4 \end{gathered}$

As I called the hamburgers as 'y', we know that he bought 4 packages of hamburgers.

5 0

1 year ago

Write an inequality to model the situation. A number exceeds 21

mezya [45]

It could be x > 21 im not sure

8 0

2 years ago

Integrate 1 - x / x(x2 + 1) d x by partial fractions.

solniwko [45]

Answer:

$log x-\frac{log(x^{2}+1) }{2}-tan^{-1} x$

Step-by-step explanation:

step 1:- by using partial fractions

$[tex]\frac{1-x}{x(x^{2}+1) } =\frac{A(x^{2}+1)+(Bx+C)(x }{x(x^{2}+1) }$ ......(1)

step 2:-

solving on both sides

$1-x=A(x^{2} +1)+(Bx+C)x......(2)$

substitute x =0 value in equation (2)

1=A(1)+0

A=1

comparing x^2 co-efficient on both sides (in equation 2)

0 = A+B

0 = 1+B

B=-1

comparing x co-efficient on both sides (in equation 2)

-1 = C

step 3:-

substitute A,B,C values in equation (1)

now

$\\\int\limits^ {} \, \frac{1-x}{x(x^{2}+1) } d x =\int\limits^ {} \frac{1}{x} d x +\int\limits^ {} \frac{-x}{x^{2}+1 } d x -\int\limits \frac{1}{x^{2}+1 } d x$

by using integration formulas

i) by using $\int\limits \frac{1}{x} d x =log x+c........(a)\\\int\limits \frac{f^{1}(x) }{f(x)} d x= log(f(x)+c\\$ .....(b)

$\int\limits tan^{-1}x dx =\frac{1}{1+x^{2} } +C$ .....(c)

step 4:-

by using above integration formulas (a,b,and c)

we get answer is

$log x-\frac{log(x^{2}+1) }{2}-tan^{-1} x$

6 0

3 years ago