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Hunter-Best [27]
3 years ago
14

From the side view, a gymnastics mat forms a right

Mathematics
2 answers:
Natali [406]3 years ago
7 0

Answer:

its b

Step-by-step explanation:

makkiz [27]3 years ago
4 0

Answer:

h=\frac{5\sqrt{3} }{3} \,\,m    

Step-by-step explanation:  

Let BC represents 5 feet across the floor, and AB represents the height.

Consider the figure in the attached file.

We know that,

\text{tan}\theta =\frac{\text{Perpendicular}}{\text{Base}}

\implies\text{tan}\,C\ =\frac{\text{AB}}{\text{BC}}

Here, \angle C=30^{\circ},\text{AB}=h\:\text{meters} , \text{and}\:\text{BC}=5\:\text{meters}

So, we have

\text{tan\,30}^{\circ}=\frac{h}{5}

\implies \frac{1}{\sqrt{3}}=\frac{h}{5}\:\:\left [ \because \text{tan\,30}^{\circ}=\frac{1}{\sqrt{3}} \right ]

\implies h=\frac{5}{\sqrt{3} }

\implies h=\frac{5\times \sqrt{3}}{\sqrt{3}\times \sqrt{3} }

\implies h=\frac{5\sqrt{3}}{3 } \,m

Hence, the mat is \frac{5\sqrt{3}}{3 } \,m high of the ground.

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Answer:

The surface area of the composite figure is 410\ m^{2}

Step-by-step explanation:

we know that

The surface area of the composite figure is equal to the surface area of the rectangular prism of the bottom plus the lateral area o the rectangular prism of the top

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