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sveta [45]
3 years ago
8

The width of a box is two inches less than twice the height. The length is 4 inches less than three times the height. The volume

is 2240 cubic inches. What are the dimensions of the box
Mathematics
1 answer:
Mrac [35]3 years ago
6 0

Answer:

Dimensions are 8 Inches by 14 inches by 20 inches

Step-by-step explanation:

The volume of the box is 2240. This means:

lbh = 2240

Where b is the width.

Width is two inches less than twice the height

b = 2h - 2

length is 4 inches less than 3 times the height

l = 3h - 4

Substituting these parameters into the lbh equation will yield the following:

h * (3h - 4) * (2h - 2) = 2240

h[6h^2-14h+8] = 2240

6h^3 -14h^2 + 8h - 2240= 0

Solving this cubic equation will yield one of the values to be 8. The other two values are complex numbers.

b = 2h - 2

l = 3h - 4

b = 2(8) - 2 = 14

l = 3(8) - 4 = 20

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Step-by-step explanation:

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3 years ago
Which polynomial correctly combines the like terms and puts the given polynomial in standard form?
Minchanka [31]

Answer: -5x^3y^3+8x^4y^2-7xy^5+x^2y^4+8x^6

Step-by-step explanation:

-5x^3y^3+8x^4y^2-xy^5-2x^2y^4+8x^6+3x^2y^4-6xy^5

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3 years ago
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Mamont248 [21]
Complementary angles add up to 90°
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3 years ago
Use the given function and the given interval to complete parts a and b. f (x )f(x)equals=negative 2 x cubed plus 21 x squared m
Leya [2.2K]

Answer:

(A)The absolute maximum of f(x) is at x=5

Step-by-step explanation:

F(x)=−2x³+21x²−60x on [1,6]

Find the first derivative.

f'(x)=-6x²+42x-60

Set the first derivative equal to zero.

-6x²+42x-60=0

Solve to find the critical points.

x=2,5

Next, we use the endpoints and all critical points on the interval to test for any absolute extrema over the given interval.

x=1,2,5,6

This is done by evaluating the function at x=1,2,5,6.

F(1)=−2(1)³+21(1)²−60(1)=-41

F(2)=−2(2)³+21(2)²−60(2)=-52

F(5)=−2(5)³+21(5)²−60(5)=-25

F(6)=−2(6)³+21(6)²−60(6)=-36

The maximum will occur at the highest f(x) value and the minimum will occur at the lowest f(x) value.

Absolute Maximum: (5,-25)

Absolute Minimum: (2,-52)

The graph is attached.

The absolute minimum and maximum of f(x) are (2,-52) and (5,-25) respectively.

3 0
3 years ago
What is the volume of the cone to the nearest cubic meter with radius of 4m and height of 5m
adoni [48]

Answer :

B) 84 m³

Step by step :

\boxed{ \bold{volume =  \frac{1}{3}\pi  {r}^{2} h }}

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6 0
3 years ago
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