Answer:
Tn=a + (n-1)d
a= first term = 14
n= This is the term you're looking for... In this case... That's the 73rd term
d=Common difference (since its an AP)
d= second term - first term -- Or 3rd term - 2nd term = 23-14
d=9
T = 14 + (73-1)9
T= 14 + (72)9
T= 14 + 648
T=662.
Answer:
$3,919.77
Step-by-step explanation:
I've taken this quiz already. It is a: $3,919.77
Answer: OPTION A.
Step-by-step explanation:
Given the following function:
You know that it represents the the height of the ball (in meters) when it is a distance "x" meters away from Rowan.
Since it is a Quadratic function its graph is parabola.
So, the maximum point of the graph modeling the height of the ball is the Vertex of the parabola.
You can find the x-coordinate of the Vertex with this formula:
In this case:
Then, substituting values, you get:
Finally, substitute the value of "x" into the function in order to get the y-coordinate of the Vertex:
Therefore, you can conclude that:
<em> The maximum height of the ball is 0.75 of a meter, which occurs when it is approximately 1 meter away from Rowan.</em>
Answer:
x = -43
y = -4
Step-by-step explanation:
In this question, you will have to find the value of x in terms of y using one of the equations and substituting the value in the other equation or vice versa.
Let's assume the numbers x and y, now we write the expressions.
x + y = -47
x - y = -39
Take the second equation and find x.
<u>Calculations:</u>
x - y = -39 (Add y on both sides)
x = -39 + y
Now that you got the value of x in terms of y, we can substitute.
<u>Calculations:</u>
(-39 + y ) + y = -47
2y - 39 = -47
2y = -8
y = -8/2 = -4
y = -4
Now that we got y, we can substitute that value in any of the equations to find x.
x - 4 = -47 or x + 4 = -39
x = -43
Answer:
905
Step-by-step explanation:
So your original equation is f(x) = x² + 5
First lets work with the stuff inside the parentheses.
f(5) = 5² + 5 = 30
So now you are finding,
f(f(5)) => f(30)
f(30) = 30² + 5 = 900 + 5 = 905
