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docker41 [41]
3 years ago
13

How to solve this equation by using elimination?

Mathematics
1 answer:
alina1380 [7]3 years ago
6 0
I believe so, correct me if I'm wrong
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Laura has 45 buttons. She gives away b buttons. Write an expression that shows the number of buttons Laura has left.
USPshnik [31]
Giving away indicates subtraction. Therefore, the expression is 45 - b.
6 0
3 years ago
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Given ​ f(x)=x2+12x+26 ​. Enter the quadratic function in vertex form in the box.
Shtirlitz [24]
Y=(x +6)^2-10 Hope this helps

3 0
3 years ago
Find FH. Help Please.​
babymother [125]

Answer:

FH = FG - HG

FH = 53 - 40

FH = 13

5 0
2 years ago
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Resistors. An electrical engineer has two boxes of resistors, with four resistors in each box. The resistors in the first box ar
Dafna11 [192]

Answer:

A. Sample Space = S = {(9, 18),(9, 19),(9, 20),(9, 21),(10, 18),(10, 19),(10, 20),(10, 21),(11, 18),(11, 19),(11, 20),(11, 21),(12, 18),(12, 19),(12, 20),(12, 21)}

B.  {(9, 18),(10, 18),(11, 18),(12, 18)}

C. {(9, 18),(9, 19),(10, 18)}

D.  {(9, 18),(9, 19),(10, 18),(11, 18),(12, 18)}

E. B(complement) ∩C =  {(9, 19)}

Step-by-step explanation:

The Sample Space would contain each element of the box A associated with each element of the box B.

A. Sample Space = S = {(9, 18),(9, 19),(9, 20),(9, 21),(10, 18),(10, 19),(10, 20),(10, 21),(11, 18),(11, 19),(11, 20),(11, 21),(12, 18),(12, 19),(12, 20),(12, 21)}

B.  Let the Outcomes in the event B, the event that the second resistor has a resistance less than 19 be denoted by J then

J=  {(9, 18),(10, 18),(11, 18),(12, 18)}

C. Let the outcomes in the event C, the event that the sum of the resistances is equal to 28 be denoted by L then

L =  {(9, 18),(9, 19),(10, 18)}

D. The  outcomes in B∪C contains all the elements of B and C

B∪C=J∪L= {(9, 18),(9, 19),(10, 18),(11, 18),(12, 18)}

E. B complement contains those elements of the Sample Space which are not the elements of Set B.

B complement= S-B=  {(9, 19),(9, 20),(9, 21),(10, 19),(10, 20),(10, 21),(11, 19),(11, 20),(11, 21),(12, 19),(12, 20),(12, 21)}

B(complement) ∩C contains those elements of B and C which are common to both B complement and C.

B(complement) ∩C =  {(9, 19)}

4 0
3 years ago
Solve the system using submsitution<br> x+y=-10<br> y=5x+2
Nitella [24]

Answer:

x+y= -10

y=5x+2

solution

x+(5x+2)= -10

x+5x+2= -10

6x+2= -10

6x= -10-2

6x= -12

6x/6= -12/6

x= -2

while y=5x+2

y= 5(-2)+2

y= -10+2

y= -8

x= -2, y= -8

4 0
2 years ago
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