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2 years ago

Line JK passes through points J(–3, 11) and K(1, –3). What is the equation of line JK in standard form?

Mathematics

1 answer:

nikitadnepr [17]2 years ago

6 0

You can start with the form
∆y(x -x1) -∆x(y -y1) = 0
Here, we have
∆y = 11-(-3) = 14
∆x = -3-1 = -4
and we can choose (x1, y1) = (1, -3). This gives
14(x -1) -(-4)(y -(-3)) = 0
14x +4y -2 = 0
All these terms have a common factor of 2 that we can remove. Adding 1 to the result puts it in standard form:

7x +2y = 1

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Answer:

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1 year ago

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Use the number 8,6, and 2 and one operation to write an expression that includes an exponent and has a value of 8. Use each numb

podryga [215]

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Solution:

Given that, Use the number 8, 6, and 2 and one operation to write an expression that includes an exponent and has a value of 8

We have to use each number only once

Given numbers are 8, 6, 2

Our expression should include exponent and the result should be 8

Among 6 and 2 we can use 2 for exponent

Raise 2 to power of 1

The expression becomes:

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3 years ago

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coldgirl [10]

Answer:

x = 9 m

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Step-by-step explanation:

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2 years ago

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So it tells us two things.

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and it tells us the closeness of the points.

Usually, anything between -0.9 and -0.6 has a moderate negative correlation. If you look at this on a graph, you will notice that the points definitely resemble a line so we say it's moderate.

It will be a negative correlation because the slope is negative.

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3 years ago

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