Answer:

Step-by-step explanation:
For this case we have defined the following events:
D= "An international flight leaving the United States is delayed in departing"
P="An international flight leaving the United States is a transpacific flight "
And we have defined the probabilities:

And for the event: "an international flight leaving the U.S. is a transpacific flight and is delayed in departing"
we know the probability:

We want to find this probability:
What is the probability that an international flight leaving the United States is delayed in departing given that the flight is a transpacific flight
So we want this probability:

And we can use the conditional formula from the Bayes theorem given two events A and B:

And if we use this formula for our case we have:

And if we replace the values we got:

Answer:
1. A possible solution for x +y is 9
Step-by-step explanation:
A possible solution for m-n is 0
Answer: OPTION C.
Step-by-step explanation:
Observe the triangle ABC attached.
Notice that the angle of depression is represented with
.
Knowing that the top of a lighthouse is 260 feet above water and the ship is 270 feet offshore, you can find the value of
by using arctangent:

In this case you can identify that:

Therefore, substuting values into
, you get that the angle of depression is:

Number 1 because of the buttcheeks in the center