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denis-greek [22]
4 years ago
13

The male elephant at the city zoo weighs 8,000 pounds, which

Mathematics
2 answers:
larisa86 [58]4 years ago
4 0
3 and a half tons is what it weighs.   
dlinn [17]4 years ago
4 0
She weighs 3 and a half tons.
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3(x-2)+6=4(2-x) simplified to an improper fraction
nika2105 [10]

Answer:

x = 8/7

Step-by-step explanation:

3(x - 2) + 6 = 4(2 - x),

3x - 6 + 6 = 8 - 4x,

7x = 8,

x = 8/7

3 0
3 years ago
This year, students in the 9th grade are collecting dimes and quarters for a school fundraiser. They are trying to collect more
BabaBlast [244]

Answer:

0.10d + 0.25q > 143.88

Step-by-step explanation:

Let the total dimes collected be d.

1\ dime = \$0.10

d\ dimes = \$0.10d

Let the total quarters collected be q.

1\ quarter = \$0.25

q\ quarters = \$0.25q

Last\ Year = \$143.88

Required

Represent as an inequality

The total collection, this year, can be represented as:

Total = 0.10d + 0.25q

From the question, we understand that:

This year's collections is expected to be greater than last year's

This can be represented as:

Total > Last\ Year

Substitute in the right values:

0.10d + 0.25q > 143.88

4 0
3 years ago
QUESTION 15 I need help
hjlf

Answer:

hhhhi

Step-by-step explanation:

I will send you a good time to be a good time to be a good time fgghgghg

7 0
3 years ago
The distribution of the weights of loaves of bread from a certain bakery follows approximately a normal distribution. Based on a
artcher [175]

Answer:

μ=23.710740....

σ=3.592592....

Step-by-step explanation:

At first, we are told that it´s a normal distribution and the following:

P(x≤15.34)=0.1

P(x≤16.31)=0.2

We start looking for those values (0.1 and 0.2) and the probabilities that gives us those values in a normal standard distribution. There´s some tools that´ll help us out but i´ll be using a chart with the values of some probabilities in a normal standard distribution (That it´s attached).

The probability of P(z≤ a.b) where "a" is the whole part of a number and "b" the decimal part is in the coordinates (a,b). For example for our problem:

P(z≤-2.33)=0.099≈0.1

P(z≤-2.06)=0.197≈0.2

To find a probability of a normal (not standard) distribution we use a method called Normalize that proceeds:

P(x≤a)=P( (x-μ)/σ ≤ (a-μ)/σ )

Where μ is the Mean of the data and σ is the Standard deviation. P( (x-μ)/σ ≤ (a-μ)/σ ) is now part of a normal standard distribution and we are able to look for it in the chart.

We will use it to find the Mean and the STD for our distribution.

P(x≤15.34)=P(z≤-2.33)≈0.1

P(x≤16.31)=P(z≤-2.06)≈0.2

so we have the equations:

(15.34 - μ)/σ= -2.33 and (16.31 - μ)/σ= -2.06

And we solve them for μ and σ:

(15.34 - μ)/-2.33= σ and (16.31 - μ)/-2.06= σ

(15.34 - μ)/-2.33 = (16.31 - μ)/-2.06

2.06*(15.34 - μ) = 2.33(16.31 - μ)

2.33μ - 2.06μ = 2.33(16.31) - 2.06(15.34)

μ= 6.4019 / 0.27

μ= 23.710740...

With this value we find σ in one equation:

(15.34 - (23.710740...)/σ = -2.33

(15.34 - (23.710740...)/-2.33 = σ

σ=3.592592...

We finally have our answers:

μ=23.710740....

σ=3.592592....

3 0
4 years ago
To calculate the volume of a cylinder, we have equation like this: V = πd 2 4 h = πr 2h d is the diameter, r is the radius and h
ycow [4]

Answer:

\delta d = +/- 0.01 mm

\delta r = +/- 0.02 mm

Step-by-step explanation:

\delta d. The error of a quantity directly measured is the uncertainty of the tool used for measuring. So error for diameter is 0.01 mm.

\delta r. The error of a quantity obtained multiplying/dividing a measure by a constant is calculated multiplying/dividing the measure uncertainity by the same constant. Radius is calculated as r=2*d, so we calculate \delta r  multiplying the diameter uncertainty by 2 (\delta r = 2*0.01=0.02).

4 0
3 years ago
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