How do you do this? Please give explanation
1 answer:
Answer:
2, 1, 3, 4, 6, 5
Step-by-step explanation:
The rate of change of function f(x) on an interval [a, b] is defined as ...
average rate of change = (f(b) -f(a))/(b -a)
For the function h(x) = 2^-x, this will be ...
arc = (h(b) -h(a))/(b -a) = (2^-b -2^-a)/(b-a) = (2^-a)(2^(a-b) -1)/(b -a)
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1. For the interval [0, 2], the average rate of change is ...
arc = (2^-0)(2^(0-2) -1)(2 -0) = (1/4 -1)/2 = -3/8 = -0.375
1 goes in the 2nd answer blank
2-6. For the other intervals, it is convenient to let a calculator or spreadsheet compute the values. The average rates of change are shown in the attachment.
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Answer:
On average, students in the 4th period did more chin-ups than students in the 2nd period
Step-by-step explanation:
Given the table values as
2nd Period 3 4 12 14 7 7 8 4 8 3 11 10 9 8 10 4 8 7 13 9
4th Period 10 3 14 14 16 15 7 12 7 10 12 8 10 9 6 11 9 1 2 5
Find the average chin-ups done by students in the gym classes
For 2nd Period gym class, the average will be;
=sum of chin-ups ÷ number of students
=sum of chin-ups in 2nd period gym class=
=number of students=20
Average=159÷20
=
For 4th Period gym class
Sum of chin-ups=
Number of students=20
Average number of chin-ups in the 4th period gym class
Average number of chin-ups in 2nd Period Class = 8
Average number of chin-ups in 4th Period Class= 9
Conclusion; On average students in the 4th period gym class made more chin-ups (9) than those in 2nd period gym class (8).