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Genrish500 [490]
3 years ago
12

Find the distance, to the nearest tenth, from T(4-2) to U(-2,3)

Mathematics
1 answer:
kiruha [24]3 years ago
4 0
Distance = SQRT(x^2+y^2)
x = 4 - (-2) = 6
y = 3 - 2 = 1

distance = SQRT(6^2 + 1^2) = SQRT(36+1) = SQRT(37) = 6.1
You might be interested in
(2.8•10^8)(1.9•10^4)
Mekhanik [1.2K]

Answer: 5.32 × 10^12

Step-by-step explanation:

This is a question relating to indices. In indices, we add the power given for question relating to multiplication. Hence, this will be:

= (2.8•10^8)(1.9•10^4)

= (2.8 × 1.9) × 10^8+4

= 5.32 × 10^12

Therefore, the answer to the question will be 5.32 × 10^12.

5 0
2 years ago
koda Buys 0.75 kg of cortos,which ia 5times the mas of the union he also Buys. How much does the union weigh?
kari74 [83]

Answer:

0.15kg

Step-by-step explanation:

Given data

We are told that

0.75 kg of cortos weights 5times the mas of the onion

We want to find the mass of 1 onion

Hence

0.75 kgcortos = 5 onions

      x cortos = 1 onions

x= 0.75/5

x= 0.15kg

Hence 1 onion will weigh 0.15kg

4 0
3 years ago
2) Subtract and simplify. 11 7\10 − 7 3\10 =
Free_Kalibri [48]

Answer:

4 2/5

Step-by-step explanation:

     11 7/10

-      7 3/10

----------------

      4 4/10

4 4/10 = 4 2/5

4 0
2 years ago
Helpp <br> Ok I don’t know how they got 3y-24
Nesterboy [21]

Answer:

y = -5/3x + 3

Step-by-step explanation:

First lets turn the equation from standard form to slope intercept form.

3x - 5y = 1

~Subtract 3x to both sides

-5y = 1 - 3x

~Divide -5 to everything

y = -1/5 + 3/5x

~Reorder

y = 3/5x - 1/5

Now that we have the equation in slope intercept form, we can find the new equation. A perpendicular line will have the opposite reciprocal of the original slope.

3/5x -> -5/3x

Now that we have the slope, we can use the given point to find the y-intercept.

y = -5/3x + b

8 = -5/3(-3) + b

8 = 5 + b

3 = b

Put all the information we solved for into a final equation.

y = -5/3x + 3

Best of Luck!

7 0
3 years ago
A cannonball is shot straight up into the air. The height of the cannonball at time t is represented by the function f(t)=−16t^2
Karo-lina-s [1.5K]

Answer:

the initial height of the cannon ball

Step-by-step explanation:

- Time (t) is basically how many seconds or minutes you factor into the given function. 16(time in exact seconds or minutes)^2+40(time in exact seconds or minutes) +5

- The +5 can only be where the cannonball was initially fired from logically. The Velocity formula is already there for you to plug the time into^^^


(I used time in minutes/seconds to try and explain what the function is asking)

8 0
3 years ago
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