Complete question :
Write a system of equations, with one equation describing the cost to bowl at Bowl-o-Rama and the other describing the cost to bowl at Bowling Pinz. For each equation, let x represent the number of games played and let y represent the total cost.
Bowl-O-Rama rents shoes for $2 and each game cost $2.50
Bowling Pinz rents shoes for $4 and each game cost $2
Answer:
Bowl-O-Rama:
y = $2 + $2.50x
Bowling pinz:
y = $4 + $2x
Step-by-step explanation:
The total cost is the sum of shoe rental plus the product of the unit game rate and the number of games played.
Total cost, y
x = number of games played
Bowl-O-Rama:
y = Shoe rent + (unit rate per game * number of games)
y = $2 + ($2.50 * x)
y = $2 + $2.50x
Bowling Pinz :
y = Shoe rent + (unit rate per game * number of games)
y = $4 + ($2 * x)
y = $4 + $2x
Answer:
<u>110.000</u>
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Step-by-step explanation:
Selling at a loss of 5% means it was sold for 95% of its purchase value.
If 120.175 equals to 95% then 100%(the purchase value) is 126.500.
120.175/95*100 = 126.500 (plenty of other ways to calculate this, but this is one of the easiest)
So now we change to the dealer's perspective, he sold the car for 126.500 and for him that meant a 15% profit. If the purchase value is 100%, then the sale value is 115% (purchase value+15% profit)
Calculate the purchase value:
126.500/115*100 = 110.000
The dealer bought the car for 110.000, sold it for 126.500, so he made a profit of 16.500 (126.500-110.000) which is a 15% profit (15% of 110.000 is 16.500).
Answer:
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Step-by-step explanation:
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