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inessss [21]
3 years ago
15

The length of a side of an equilateral triangle is 12. find the length of the altitude

Mathematics
1 answer:
dalvyx [7]3 years ago
6 0
Sqrt(12^2 - 6^2) = sqrt(144-36) = sqrt(108) = 6sqrt(3)
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X^2-7x=0 solve the equation​
inn [45]

Answer:

x = 0, 7

Step-by-step explanation:

Step 1: Write out equation

x² - 7x = 0

Step 2: Factor out <em>x</em>

x(x - 7) = 0

Step 3: Find roots

x = 0

x - 7 = 0

x = 7

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a

Step-by-step explanation:

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Given the following trigonometric ratio, enumerate the meaning ratio ​
Likurg_2 [28]

Answer:

The trigonometric ratios are presented below:

\sin \theta = \frac{AC}{\sqrt{AC^{2} + BC^{2}}}

\cos \theta = \frac{BC}{\sqrt{AC^{2} + BC^{2}}}

\cot \theta = \frac{BC}{AC}

\sec \theta = \frac{\sqrt{AC^{2}+BC^{2}}}{BC}

\csc \theta = \frac{\sqrt{AC^{2}+BC^{2}}}{AC}

Step-by-step explanation:

From Trigonometry we know the following definitions for each trigonometric ratio:

Sine

\sin \theta = \frac{y}{h} (1)

Cosine

\cos \theta = \frac{x}{h} (2)

Tangent

\tan \theta = \frac{\sin \theta}{\cos \theta} = \frac{y}{x} (3)

Cotangent

\cot \theta = \frac{\cos \theta}{\sin \theta} = \frac{x}{y} (4)

Secant

\sec \theta = \frac{1}{\cos \theta} = \frac{h}{x} (5)

Cosecant

\csc \theta = \frac{1}{\sin \theta} = \frac{h}{y} (6)

Where:

x - Adjacent leg.

y - Opposite leg.

h - Hypotenuse.

The length of the hypotenuse is determined by the Pythagorean Theorem:

h = \sqrt{x^{2}+y^{2}}

If y = AC and x = BC, then the trigonometric ratios are presented below:

\sin \theta = \frac{AC}{\sqrt{AC^{2} + BC^{2}}}

\cos \theta = \frac{BC}{\sqrt{AC^{2} + BC^{2}}}

\cot \theta = \frac{BC}{AC}

\sec \theta = \frac{\sqrt{AC^{2}+BC^{2}}}{BC}

\csc \theta = \frac{\sqrt{AC^{2}+BC^{2}}}{AC}

6 0
3 years ago
Hannah has a rectangular prism with a length of 7 cm, a width of 2 cm,
weeeeeb [17]

Answer:

Area =136cm²

Area =2(wl+hl+hw)=2·(2·7+6·7+6·2)=136cm²

4 0
3 years ago
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