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Setler79 [48]
3 years ago
6

Evaluate

Mathematics
1 answer:
lora16 [44]3 years ago
7 0

Answer:

8

Step-by-step explanation:

the top part with the variables filled in is 0 + (2x4) + (3x4x2) which is 32

the bottom part would be (3x0) + 4 which is 4

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Which could be used to solve this equation? 3 1/5 +n =9
MaRussiya [10]

Answer:

A

Step-by-step explanation

You need to subtract the 3 1/5 from both sides, which gives you 29/5

7 0
3 years ago
The mean number of words per minute (WPM) read by sixth graders is 97 with a standard deviation of 19 WPM. If 75 sixth graders a
andrey2020 [161]

Answer:

0.0174 = 1.74% probability that the sample mean would be greater than 101.63 WPM

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}};

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 97, \sigma = 19, n = 75, s = \frac{19}{\sqrt{75}} = 2.1939

What is the probability that the sample mean would be greater than 101.63 WPM?

This is 1 subtracted by the pvalue of Z when X = 101.63. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{101.63 - 97}{2.1939}

Z = 2.11

Z = 2.11 has a pvalue of 0.9826.

1 - 0.9826 = 0.0174

0.0174 = 1.74% probability that the sample mean would be greater than 101.63 WPM

5 0
3 years ago
Please help with the first question....
Morgarella [4.7K]

Answer:

  A)  The functions are not inverses of each other.

Step-by-step explanation:

f(g(x))=\sqrt{(x^2+3)-3}=\sqrt{x^2}=|x|\ne x

The result of f(g(x)) is not always x, so the functions are not inverses of each other.

In general, a quadratic (or any even-degree polynomial) such as g(x) cannot have an inverse function because it does not pass the horizontal line test.

7 0
3 years ago
Help please ten points I’ll mark brailiest
Mama L [17]

KJ, IK, HI, HK, then HJ

i think this is it. hope it helps!! :)

7 0
3 years ago
PLEASE HELP ME ANSWER ASAP!
Blizzard [7]
Either twice or more than twice. But I’d go with twice
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3 years ago
Read 2 more answers
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