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3 years ago

What is the distance between the points (4,7) and (4,-5)?

Mathematics

2 answers:

elena-14-01-66 [18.8K]3 years ago

5 0

$\sqrt{(x2-x1)^2+(y2-y1)^2} 

 \sqrt{(4-4)^2+(-5-7)^2} = 12 Units.$

Hope this loves.

ololo11 [35]3 years ago

5 0

Answer:

the answer is 12

Step-by-step explanation:

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Simplify the expression below. 2x - 10 + 6x

PtichkaEL [24]

Answer:

8x - 10

Step-by-step explanation:

Combine like terms:

2x + 6x - 10

= 8x -10

4 0

2 years ago

Read 2 more answers

1. How many squares do I shade on 10 square grid for 60% of 40 ?

Sholpan [36]

Answer:

Either 2.4 boxes or 6

Step-by-step explanation:

10% of 40 is 4

60% of 40 is 24

Either 2.4 boxes or 6

6 0

2 years ago

1 2/3*J=15 What is J?

Wewaii [24]

Answer:

Do you mean:

(1+(2/3))j = 15

((3/3)+(2/3))j = 15

((3+2)/3)j = 15

(5/3)j = 15

j = 15 / (5/3)

j = 15 * (3/5)

j = 9

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

At the beginning of year 1, Bode invests $250 at an annual simple interest rate of 3%. He makes no deposits to or withdrawals fr

xz_007 [3.2K]

Answer:

D.A(n) = 250 + (n – 1)(0.03 • 250); $347.50

Step-by-step explanation:

we know that

The simple interest formula is equal to

$A=P(1+rt)$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest

t is Number of Time Periods

in this problem we have

$t=(14-1)=13\ years\\ P=\$250\\r=0.03$

substitute in the formula above

$A=\$250(1+0.03*13)$

$A=\$250(1.39)=\$347.50$

8 0

3 years ago

In the following problem, check that it is appropriate to use the normal approximation to the binomial. Then use the normal dist

Tcecarenko [31]

Answer:

a. 0.7291

b. 0.9968

c. 0.7259

Step-by-step explanation:

a. np and n(1-p) can be calculated as:

$np=23\times 0.48\\\\=11.04\\\\n(1-p)=23(1-0.52)\\\\=11.96$

#Both np and np(1-p) are greater than 5, hence, normal approximation is most appropriate:

$\mu_x=11.04\\\\\sigma^2=np(1-p)=0.48\times 0.52\times 23=5.7408$

#Define Y:

Y~(11.04,5.7408)

$P(X\leq 12)\approx P(Y\leq 12.5)\\\\P(Z\leq \frac{(12.5-11.04)}{\sqrt{5.7408}})=\\\\=1-0.2709\\\\=0.7291$

Hence, the probability of 12 or fewer is 0.8291

b. The probability that 5 or more fish were caught.

#Using normal approximation:

$P(X \geq 5) \approx P(Y \geq 4.5) = P(Z \geq\frac{ (4.5-11.04)}{\sqrt{(5.7408)}})\\\\=1-0.0032\\\\=0.9968$

Hence, the probability of catching 5+ is 0.9968

c. The probability of between 5 and 12 is calculated as;

-From b above $P(X\geq 5)=0.9968$ and a , $P(X\leq 12)$ =0.7291

$P(5\leq X\leq 120\approx P(4.5\leq Y\leq 12.5)\\\\=0.7291-(1-0.9968)\\\\=0.7259$

Hence, the probability of between 5 and 12 is 0.7259

4 0

3 years ago