We are given the equation <span>an = (n^2/ sqrt(n^3+4n)) and asked to determine if the function is divergent or convergent. In this case, we find the limit of the function as n approaches infinity.
an = </span><span> (n^2/ sqrt(n^3+4n))
lim (n to infinity ) = infinity / infinty: ;indeterminate
Using L'hopitals rule, we derive
</span><span>lim (n to infinity ) = 2 n / 0.5* ( </span><span>n^3+4n) ^-0.5 * (3 n2 +4) : infinity / infinity
again, we derive
</span>lim (n to infinity ) = 2 (0.25) (( n^3+4n) ^-0.5))*(3 n2 +4) / 0.5* ( 6n + 4) :infinity / infinity
<span>
again,
</span>lim (n to infinity ) = 2 (0.25) (6n + 4) / 0.5* ( 6)* 0.5 <span>(( n^3+4n) ^-0.5))</span>
this goes on and the function is divergent
Frequency = 1/period
Frequency = 1 / 0.001136
Frequency = 880.2816 Hz
Rounded to the nearest frequency = 880 Hz
Answer:
A
Step-by-step explanation:
Volume = area of base * height = pi r^2 h
D is correct
