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Nataly_w [17]
2 years ago
14

Please help me! I am trying to complete this question!​

Mathematics
2 answers:
Iteru [2.4K]2 years ago
7 0

Answer:

131.25 in ^2

Step-by-step explanation:

Find the area of the rectangle on the left

A = l*w

A = 11.75 * 6 = 70.5 in ^2

Now find the area of the rectangle on the right

The length is 9 and  the height is 11.75 - 5 = 6.75

A = 9 * 6.75

A = 60.75 in ^2

Add the areas together

70.5+60.75 = 131.25 in ^2

Natasha2012 [34]2 years ago
6 0

Answer:131.25

Step-by-step explanation:

11 3/4 x 6 = 70.5 (area of first rectangle)

11 3/4 - 5 = 6.75 (to find the height of the other figure)

6.75 x 9 = 60.75 (area of 2 figure)

60.75 + 70.5 = 131.25

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Well cutting off the small 4x2 you get 8 plus’s the 7x2 is 14 so just add those together you should get 22in ^2
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Write the equation in slope-intercept form. 5x+3y=12
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5x+3y=12
Subtract 5x from both sides
3y=-5x+12
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2 years ago
If 2a+3b=12 and ab=6 find the value of 8a^3+27b^3
Alex17521 [72]
<span>A) 2a + 3b = 12
B) ab = 6 solving for a
B) a = 6 / b then we substitute this into equation A)
</span><span>A) 12 / b + 3b = 12  </span><span>multiplying this by "b"
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A) b^2 -4b + 4 = 0
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6 0
3 years ago
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A pool measuring 18 meters by 22 meters is surrounded by a path of uniform width. If the area of the pool and the path combined
suter [353]

Answer: the width of the uniform path is 9 meters.

Step-by-step explanation:

Let x represent the width of the uniform path.

A pool measuring 18 meters by 22 meters is surrounded by a path of uniform width. It means that the combined length of the pool and the uniform path is (18 + 2x) meters and the combined width of the pool and the uniform path is (22 + 2x) meters.

If the area of the pool and the path combined is 1440 square meters, it means that

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Dividing both sides of the equation by 4, it becomes

x² + 20x - 261 = 0

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x - 9 = 0 or x + 29 = 0

x = 9 or x = 29

Since the width cannot be negative, then x = 9 meters

5 0
2 years ago
Find the missing side length, round to the nearest hundredth.
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Answer:

Pythagoras theorem.

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x²=15²+12²

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x²=329

x=329½

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