Well cutting off the small 4x2 you get 8 plus’s the 7x2 is 14 so just add those together you should get 22in ^2
5x+3y=12
Subtract 5x from both sides
3y=-5x+12
Divide by 3
Y=-5/3x +4
<span>A) 2a + 3b = 12
B) ab = 6 solving for a
B) a = 6 / b then we substitute this into equation A)
</span><span>A) 12 / b + 3b = 12 </span><span>multiplying this by "b"
A) 12 + 3b^2 = 12b
A) 3b^2 -12b +12= 0 dividing by "3"
A) b^2 -4b + 4 = 0
Factoring
(b-2) * (b-2) = 0
b = 2
Since b = 2 then a = 3
</span>NOW, we put these numbers into:
<span>8a^3 +27b^3
</span>
8*3*3*3 + 27*2*2*2
216 + 216
The answer is 512
Answer: the width of the uniform path is 9 meters.
Step-by-step explanation:
Let x represent the width of the uniform path.
A pool measuring 18 meters by 22 meters is surrounded by a path of uniform width. It means that the combined length of the pool and the uniform path is (18 + 2x) meters and the combined width of the pool and the uniform path is (22 + 2x) meters.
If the area of the pool and the path combined is 1440 square meters, it means that
(18 + 2x)(22 + 2x) = 1440
396 + 36x + 44x + 4x² = 1440
4x² + 80x + 396 - 1440 = 0
4x² + 80x - 1044 = 0
Dividing both sides of the equation by 4, it becomes
x² + 20x - 261 = 0
x² + 29x - 9x - 261 = 0
x(x + 29) - 9(x + 29) = 0
x - 9 = 0 or x + 29 = 0
x = 9 or x = 29
Since the width cannot be negative, then x = 9 meters
Answer:
Pythagoras theorem.
hypotenuse²=height²+base²
x²=15²+12²
x²=225+144
x²=329
x=329½
x=19.20
