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Elanso [62]
3 years ago
5

X^2y^8/x^7y^6 if x= -2 and y= 4

Mathematics
1 answer:
damaskus [11]3 years ago
7 0

Answer:

- \frac{1}{2}

Step-by-step explanation:

Given

\frac{x^2y^8}{x^7y^6}

= \frac{y^{(8-6)} }{x^{(7-2)} }

= \frac{y^2}{x^5} , substitute values

= \frac{4^2}{(-2)^{5} }

= \frac{16}{-32}

= - \frac{1}{2}

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