Question

X^2y^8/x^7y^6 if x= -2 and y= 4

Answer 1

Answer:

- $\frac{1}{2}$

Step-by-step explanation:

Given

$\frac{x^2y^8}{x^7y^6}$

= $\frac{y^{(8-6)} }{x^{(7-2)} }$

= $\frac{y^2}{x^5}$ , substitute values

= $\frac{4^2}{(-2)^{5} }$

= $\frac{16}{-32}$

= - $\frac{1}{2}$