3 years ago

X^2y^8/x^7y^6 if x= -2 and y= 4

Mathematics

1 answer:

damaskus [11]3 years ago

7 0

Answer:

- $\frac{1}{2}$

Step-by-step explanation:

Given

$\frac{x^2y^8}{x^7y^6}$

= $\frac{y^{(8-6)} }{x^{(7-2)} }$

= $\frac{y^2}{x^5}$ , substitute values

= $\frac{4^2}{(-2)^{5} }$

= $\frac{16}{-32}$

= - $\frac{1}{2}$

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