A line that is parallel to a side and intersects the other two siddes divides the sides proportionally.
Set up the proportion
2/x+1 = x/x+6
Multiply means and extremes
2x+12= x^2+ x
Solve to get your answer.
Answer: 80 votes
Step-by-step explanation: Solve the formula for l. A) l ... 01/18/2017. Mathematics · High School. answered. The surface area of a cone is given by the formula S = πl + πr2. ... all of the 2's are to the power of R the 5/3.14's are fractions. 2 ... Incognit-oh-no… ... and 219 more users found this answer helpful. Thanks 140. 4.7. (80 votes).
Answer:120000
Step-by-step explanation:
bc in a minute their is 60 seconds and if the leoperd runs 500 yards every 30 seconds u would multiply 60 times 2 bc their is 60 min in a hour and u would get 120.then u would multiply that by 2 getting u 240 which is two hours then u would do 500 times 240
Answer:
11.81 minutes
Step-by-step explanation:
Here is a simple step-by-step explaination of how to solve this word problem:
Since the truck has 2,400L in it to begin with, the first part of our equation will be 2,400L

Next we know that the water in the truck decreases at a <u>rate</u> of 110L/min, or <u>Liters per minute</u>.
So we will put that in the equation:

Now that we have our equation set up, its time to solve.
To figure out how much water it needs to lose in <u>total</u> to end up with 1100 L left, we subtract 1,100 from 2,400.

Now we can take that number and divide it by how many liters per minute were lost.
So the total amount of time it took for the truck to have 1,100 L left is 11.81 minutes. Your answer would be
B.
min
Hope this helps! : )
9514 1404 393
Answer:
y = 3.02x^3 -5.36x^2 +5.68x +8.66
Step-by-step explanation:
Your graphing calculator (or other regression tool) can solve this about as quickly as you can enter the numbers. If you have a number of regression formulas to work out, it is a good idea to become familiar with at least one tool for doing so.
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If you're trying to do this by hand, the x- and y-values give you 4 equations in the 4 unknown coefficients.
a·1^3 +b·1^2 +c·1 +d = 12
a·3^3 +b·3^2 +c·3 +d = 59
a·6^3 +b·6^2 +c·6 +d = 502
a·8^3 +b·8^2 +c·8 +d = 1257
Solving this by elimination, substitution, or matrix methods is tedious, but not impossible. Calculators and web sites can help. The solutions are a = 317/105, b = -75/14, c = 1193/210, d = 303/35. Approximations to these values are shown above.