Answer:
2y^2+18x
Step-by-step explanation:
4y^2 + 6x -2y^2 + 12x
=4y^2-2y^2+6x+12x
=2y^2+6x+12x
=2y^2+18x
a. 6, 8, 10, 12, 14
Work:
a_1 = 2(1) + 4
a_1 = 6
a_2 = 2(2) + 4
a_2 = 8
a_3 = 2(3) + 4
a_3 = 10
a_4 = 2(4) + 4
a_4 = 12
a_5 = 2(5) + 4
a_5 = 14
b. 500
Work:
Since the common difference is 2, we can add 2 to each number until we reach the 20th term.
6 + 8 + 10 + 12 + 14 + 16 + 18 + 20 + 22 + 24 + 26 + 28 + 30 + 32 + 34 + 36 + 38 + 40 + 42 + 44 = 500
Since the jet bomber arrived over its Target at the same time as its fighter jet escorted, it took the jet bomber 0.34 h to reach the target.
<h3 />
To find the number of hours, we need to solve simultaneous equations.
<h3>
What are simultaneous equations?</h3>
Simultaneous equations are pair of equations which contain two unknowns.
<h3>How to calculate the number of hours the bomber jet took off?</h3>
Let
- D = distance travelled by both bomber jet and fighter jet.
- t = time bomber jet took off
- v = speed of bomber jet.
- T = time fighter jet took off and
- V = speed of fighter jet.
So, D = vt
D = 500t (1)
Also, D = VT
D = 60T (2)
Since jet bomber traveling 500 mph arrived over its Target at the same time as its fighter jet escorted which left the same fate 2.5 hours after the bomb took off.
T = t + 2.5
So, D = 60(t + 2.5) (3)
<h3>
The required simultaneous equations</h3>
D = 500t (1)
D = 60(t + 2.5) (3)
Equating equations (1) and (3), we have
500t = 60(t + 2.5)
500t = 60t + 150
500t - 60t = 150
440t = 150
t = 150/440
t = 15/44
t = 0.34 h
So, it took the jet bomber 0.34 hours to reach the target.
Learn more about simultaneous equations here:
brainly.com/question/27829171
#SPJ1
Answer:
a=79
Step-by-step explanation:
you do the math and search it up
Answer:
891 pickles :)
Step-by-step explanation:
all you do is multiply 9 and 99 and you should get 891
Hope this helped
