Take the derivative:
g’(x) = 12x^3 - 24x^2
Set equal to zero and solve:
0 = 12x^3 - 24x^2
0 = 12x^2 (x - 2)
x = 0 or x = 2
Plug back into original
g(0) = 3(0^4) - 8(0^3)
g(0) = 0 - 0
g(0) = 0
g(2) = 3(2^2) - 8(2^3)
g(2) = 3(4) - 8(8)
g(2) = 12 - 64
g(2) = -52
There is an absolute max at (0,0) or when x = 0
£17.50 is 50% of what number
Now the same in math:
£17.50 = .50 x n pr £17.50 = .5n
Divide both sides by .5
n= £ 35
Check the picture below. You can pretty much just count the units off the grid.
The difference between 1/2 and 1/6 is 2/6. So to write an expression we could do x divided by 2/6=2/3. So instead of a division expression, we could make that into a multiplication problem 2/6 times 2/3=x. 2/6 times 2/3= 4/18 so your answer is 4/18 or 2/9
