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Zinaida [17]
2 years ago
11

Round 10,982 to the nearest thousand

Mathematics
1 answer:
nadezda [96]2 years ago
4 0
11,000 - rounded to the nearest thousand!
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The diameter of a circle has endpoints A(1, 3) and B(4, 7), what is the
lana [24]

Answer:

The circumference of the circle is 5π

Step-by-step explanation:

First we need to calculate the diameter  

for this we have to know the distance between A(1, 3) and B(4, 7)

X =  Xb - Xa

X = 4 - 1

X = 3

Y = Yb - Ya

Y = 7 - 3

Y = 4

b - a = (3 , 4)

now that we have the distance of x and r we can calculate its distance using Pythagoras

h = hypotenuse

x = leg 1 = 3

y = leg 2 = 4

h² = x² + y²

we replace the known values

h² = (3)² + (4)²

h² = 9 + 16

h² = 25

h = √25

h = 5

The diameter of the circle is 5

Now we need to calculate the circumferencefor this we need to use the circumferenc formula of a circle:

c = circumference

d = diameter = 5

π = pi

c = π * d

we replace with the known values

c = 5  * π

c = 5π

The circumference of the circle is 5π

4 0
3 years ago
You build and sell toy cars for $36 each. So far, you have built 25 toy cars. How many more toy cars will you have to build and
vovikov84 [41]
You need to build 20 more toy cars
8 0
3 years ago
Read 2 more answers
Solve this please!!!!
Lilit [14]
Answer it’s 14

Explanation
Look at the middle letters from the three of them ( BNO) always pick the middle letter (N) like look at this

6 0
3 years ago
Please Help me with this
Elden [556K]
1) he is not reasonable because pounds per feet would mean you would do 7.3/14.6 which is a decimal

hope this helped :)
7 0
3 years ago
10.5% of the population is 65 or older. Find the probability that the following number of persons selected at random from 25 peo
julia-pushkina [17]

Given:

The sample size n=25

Probability of population is 65 or older is 10.5%.

This date follows the binomial distribution,

\begin{gathered} n=25,p=0.105 \\ X\rightarrow B(n=25,p=0.105) \end{gathered}

To find the probability that at most 2 are 65 or older,

\begin{gathered} P(X=x)=^nC_x(p)^x(1-p)^{n-x} \\ P(0\leq X\leq2)=P(X=0)+P(X=1)+P(X=2) \\ =^{25}C_0(0.105)^0(1-0.105)^{25-0}+^{25}C_1(0.105)^1(1-0.105)^{25-1}+^{25}C_2(0.105)^2(1-0.105)^{25-2} \\ =0.0625+0.1832+0.2579 \\ =0.5036 \\ \approx0.504 \end{gathered}

Answer: Probability is 0.504 .

8 0
1 year ago
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