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Zinaida [17]
2 years ago
11

Round 10,982 to the nearest thousand

Mathematics
1 answer:
nadezda [96]2 years ago
4 0
11,000 - rounded to the nearest thousand!
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Show the region which satisfies simultaneously the inequalities 2x+3y≤8, x-2y≥-3, x≥0, y≥0
Verizon [17]
The first thing you should do is graph the following lines
 2x + 3y = 8
 x-2y = -3
 x = 0
 y = 0
 After you have graphed them, you should proceed to evaluate points in the xy plane that meet the following restrictions:
 2x + 3y≤8, x-2y≥-3, x≥0, y≥0
 The resulting region is the region "R" shown in the attached graph.

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2 years ago
8X 1 + 5 X 1/100 + 9 X 1/1000
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I hope this helps you

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Hey there! :)

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B . tell me if ya need proof

Step-by-step explanation:

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