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3 years ago

An ordered pair with a a negative x and positive y coordinate is located in which quadrant?

Mathematics

2 answers:

Ivanshal [37]3 years ago

6 0

Answer:

Quadrant II

Step-by-step explanation:

Quadrant I is ( + , + )

Quadrant II is ( - , + )

Quadrant III is ( - , - )

Quadrant IV is ( + , - )

klasskru [66]3 years ago

3 0

It is located in Quadrant II

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Use greatest common factor and the distributive property to write equivalent expressions in factored form for the following expr

Nitella [24]

Answer:

a. 4(d+3e)

b. 6(3x+5y)

c. 7(3a+4y)

d. 8(3f+7g)

Step-by-step explanation:

In each case we find the greatest common factor of the numbers. That is the greatest number that goes into both the numbers. Then we factor it out in front and inside parentheses we divide each original term by the greatest common factor:

a. 4d+12e, GCF: 4

$\displaystyle4\left(\frac{4d}{4}+\frac{12e}{4}\right)=4(d+3e)$

b. 18x+30y, GCF: 6

$\displaystyle6\left(\frac{18x}{6}+\frac{30y}{6}\right)=6(3x+5y)$

c. 21a+28y, GCF: 7

$\displaystyle7\left(\frac{21a}{7}+\frac{28y}{7}\right)=7(3a+4y)$

d. 24f+56g, GCF: 8

$\displaystyle8\left(\frac{24f}{8}+\frac{56g}{8}\right)=8(3f+7g)$

5 0

4 years ago

Mr. Gardener has $300,000 in a deposit account and receives 8 1 3 % interest annually. What annual interest (in dollars) does he

Luba_88 [7]

Answer:

The annual interest he receives is $25000

Step-by-step explanation:

We are given

Mr. Gardener has $300,000 in a deposit account

so,

P=300000

receives 8 1 3 % interest annually

so, r=8 1/3 %

$r=8\frac{1}{3} =\frac{8\times 3+1}{3} =\frac{25}{3}$ %

time =1 year

so, t=1

now, we can use interest formula

$I=\frac{P\times r\times t}{100}$

now, we can plug values

$I=\frac{300000\times \frac{25}{3}\times 1}{100}$

now, we can simplify it

$I=25000$

So,

The annual interest he receives is $25000

3 0

4 years ago

Read 2 more answers

3-) Martha O'Brien made a deposit to her checking account at an ATM and received

Mademuasel [1]

Answer:

The amount Martha deposited in checks is $150

The amount Martha deposited in cash is $100

The total deposit is $175

Step-by-step explanation:

Since Total deposit (T) = currency (C) + coins + check (Ck) - cash received (Csh)

T = C + Ck - Csh. (1)

Given that cash received (Csh) = $75,coins = 0 and the checks deposited totaled $50 less than twice the currency amount. So,

Ck = 2C - $50 (2)

Also, total deposit was $25 more than the check amount. So,

T = Ck + $25 (3)

Substituting equation (2) into (1), we have

T = C + Ck - Csh

T = C + 2C - $50 - Csh

T = 3C - $50 - $75

T = 3C - $125 (4)

Substituting equation (2) into (3), we have

T = Ck + $25

T = 2C - $50 + $25

T = 2C - $25 (5)

Equating equations (4) and (5), we have

3C - $125 = 2C - $25

Collecting like terms, we have

3C - 2C = $125 - $25

C = $100

Substituting C into (2), we have

Ck = 2C - $50

Ck = 2($100) - $50

Ck = $200 - $50

Ck = $150

We now compute T

T = C + Ck - Csh.

T = $100 + $150 - $75.

T = $250 - $75

T = $175

So, the amount Martha deposited in checks is $150

The amount Martha deposited in cash is $100

The total deposit is $175

5 0

3 years ago

The axis of symmetry for a function in the form f(x) = x^2 + 4x − 5 is x = −2. What are the coordinates of the vertex of the gra

Murrr4er [49]

I'm sure you already know the axis which is x= -2. The vertex is (-2,-9). You can use the graph or solve to find the vertex. I hope this helpful.

8 0

4 years ago

Joseph has a collection of stickers. When the stickers are aranged in piles of 3, there are 2 stickers left over. When the stick

Elodia [21]

Answer:

2 stickers will be left over

Step-by-step explanation:

To answer the question, all you need to do is figure out at what value of stickers would the remaining stickers be equal to 2 if the piles are made up of either 3 to a set or 4 to a set. To do this, we need to figure out the size of the whole set of stickers.

Lets assume that the total number of stickers is 14. Lets test the 2 given conditions. If we divide it in piles of 3 then we will have a pile of 12 stickers (4 piles of 3 stickers each) with 2 stickers remaining.

Lets test the second condition. If we divide it in piles of 4, we will again have 12 stickers (3 piles of 4 stickers each) with 2 stickers remaining.

Now that both conditions have been satisfied, all we have to do is see how many stickers are left if we make a pile of 12 stickers. In this case, we will have just one pile of 12 stickers and, again, we will be left with 2 stickers.

Therefore, the answer is 2 stickers

6 0

3 years ago