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zloy xaker [14]
3 years ago
9

An ordered pair with a a negative x and positive y coordinate is located in which quadrant?

Mathematics
2 answers:
Ivanshal [37]3 years ago
6 0

Answer:

Quadrant II

Step-by-step explanation:

Quadrant I is ( + , + )

Quadrant II is ( - , + )

Quadrant III is ( - , - )

Quadrant IV is ( + , - )

klasskru [66]3 years ago
3 0
It is located in Quadrant II
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Find the sum and product of the roots.
xz_007 [3.2K]

Answer:

sum= -3 product=-4

Step-by-step explanation:

2x^2-2x+8x-8

2x(x-1)+8(x-1)

(2x+8)(x-1)

x=-4 x=1

8 0
4 years ago
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The perimeter of a rectangle can be found using the equation P = 2L + 2W, where P is the perimeter, L is the length, and
a_sh-v [17]

Answer:

No, that is not possible

Explanation:

P = 2L + 2W

Insert numbers into equation

p=(2)(20)+(2)(11)

Step 1: Simplify both sides of the equation.

p=(2)(20)+(2)(11)

p=40+22

p=(40+22)(Combine Like Terms)

p=62

p=62

The perimeter is 62, not 64, so the perimeter can't be 64 if the length 20 and the width is 11.

7 0
4 years ago
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Help me!!!!!!!!!!!!!!
Dominik [7]

Answer:

use brainly points

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Brainliest + 20 pts to whoever helps pls!!
Blizzard [7]

Answer:

Correct option is (a). 60.391 and 101.879; because the test statistic is in a critical region, the test rejects the null hypothesis.

Step-by-step explanation:

A Chi-square test for population variance is used to perform this test.

The standard deviation is, 2.0 minutes.

Then the variance is, 4.0 minutes.

The hypothesis for this test is:

<em>H₀</em>: The population variance of all commute times is equal to 4.0 minutes, i.e. <em>σ² </em>= 4.

<em>Hₐ</em>: The population variance of all commute times is not equal to 4.0 minutes, i.e. <em>σ² </em>≠ 4.

The test statistic is:

\chi^{2}_{calc.}=\frac{(n-1)s^{2}}{\sigma^{2}}

The critical region of this test is defined as:

Reject <em>H₀</em> if \chi^{2}_{calc.} or \chi^{2}_{calc.}>\chi^{2}_{(1-\alpha /2), (n-1)}.

The degrees of freedom is:

n-1=81-1=80

Compute the critical from a Chi-square table.

\chi^{2}_{\alpha /2, (n-1)}=\chi^{2}_{0.05, 80}=101.879\\\chi^{2}_{(1-\alpha /2), (n-1)}=\chi^{2}_{0.95, 80}=60.391\\

The test statistic value is, \chi^{2}_{calc.}=105.8.

\chi^{2}_{calc.}=105.8 > \chi^{2}_{0.05, 80}=101.879

The null hypothesis is rejected because the test statistic is in the critical region.

Thus, the correct option is (a).

6 0
3 years ago
Mr. Marcos, the gym teacher, had the seventh graders run around the perimeter of the gym 3 times.The gym has a length of 34 feet
natka813 [3]
So 34 x 58 = 1972 which is the area of the whole gym. Now they ran 3 times so 1972 x 3 = 5916. 
4 0
3 years ago
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