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3 years ago

Which function has the same y-intercept as the function

Mathematics

1 answer:

ddd [48]3 years ago

8 0

The answer is 6x-7y=21

In order to find this answer you need to convert the answer choices into y intercept form by isolating the y variable to one side of the equation.
6x-7y=21
-7y=-6x+21
y=6/7x-3
As you can see when you change the form of this equation, the y intercept is -3.

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6 (2x+7) = 5 x - 11 - x

Delvig [45]

Answer:

x = -53/8

Step-by-step explanation:

6(2x + 7) = 5x - 11 - x

12x + 42 = 5x -11 - x (Distributive property)

12x + 42 = 4x - 11 (Subtraction property)

8x + 42 = -11 (Subtraction Property)

8x = -53 (Subtraction Property)

4 0

3 years ago

Read 2 more answers

Follow the steps to find the

KIM [24]

The area of the sector rounded to 4 decimal place is 78.6396 cm²

<h3 /><h3>How to find the area of a sector?</h3>

area of sector = ∅/ 360 × πr²

Therefore,

r = radius

∅ = 46 degrees.

Hence,

area of a sector = 46 / 360 × 3.14 × 14²

area of a sector = 46 / 360 × 3.14 × 196

area of a sector = 46 / 360 × 615.44

area of a sector = 28310.24 / 360

area of a sector = 78.6395555556

Hence,

area of a sector = 78.6396 cm²

learn more on sector here: brainly.com/question/27946869

#SPJ1

6 0

2 years ago

What are the coordinates of the vertex of the function f(x) = x2 - 12x + 5?

FinnZ [79.3K]

Answer:

The vertex is the point (6,-31)

Step-by-step explanation:

we have

$f(x)=x^2-12x+5$

This is a vertical parabola open upward

The vertex represent a minimum

Convert to vertex form

Complete the square

$f(x)=(x^2-12x+6^2)+5-6^2$

$f(x)=(x^2-12x+36)-31$

Rewrite as perfect squares

$f(x)=(x-6)^2-31$ -----> equation in vertex form

therefore

The vertex is the point (6,-31)

6 0

3 years ago

1/4 + 7/8 = ?<br> 2/3<br> 5/8<br> 1 1/8<br> 13/4

Marta_Voda [28]

Answer:

Step-by-step explanation:

1/4 + 7/8 =

2/8 + 7/8 Convert the 1/4 to the denominator as 8 so we can add the top number.

9/8 Add the top number.

1 1/8 Simplifly the result.

4 0

2 years ago

Read 2 more answers

What is the inverse of the function g(x) = x^3/8 + 16 ?

lesya692 [45]

Answer:

$\hookrightarrow \: { \rm{f(x) = \frac{ {x}^{3} }{8} + 16}} \\$

• let f(x) be m:

${ \rm{m = \frac{ {x}^{3} }{8} + 16}} \\$

• make x the subject of the function:

${ \rm{8m = {x}^{3} + 128}} \\ \\ { \rm{ {x}^{3} = 8m - 128 }} \\ \\ { \rm{ {x}^{3} = 8(m - 16) }} \\ \\ { \rm{x = \sqrt[3]{8} \times \sqrt[3]{(m - 16)} }} \\ \\ { \rm{x = 2 \sqrt[3]{(m - 16)} }}$

• therefore:

${ \boxed{ \rm{ {f}^{ - 1} (x) = 2 {(m - 16)}^{ \frac{1}{3} } }} }\\$

6 0

2 years ago