Question

What is the equation of a line, in point slope form that passes through (-2, -6) and has a slope of 1/3 ​

Answer 1

Answer:

The equation of a line, in point slope form that passes through (-2, -6) and has a slope of 1/3 ​is $y+6=\frac{1}{3}(x+2)$

Solution:

Given that line passes through (-2, -6) and has slope of 1/3

We have to find the equation of the line

The point slope form is given as

$y-b=m(x-a)$

where m is the slope of the line and a, b are the x, y coordinates of the given point through which the line passes.

Here in this question, m = 1/3 and a = -2 and b = -6

By substituting in point slope form we get,

$y - (-6) = \frac{1}{3}(x - (-2))\\\\y + 6 = \frac{1}{3}(x + 2)$

Hence the equation of a line, in point slope form that passes through (-2, -6) and has a slope of 1/3 ​is $y+6=\frac{1}{3}(x+2)$