Ok, so:
For Part A, we have: P(Z|A)=P(Z and A)/P(A)
And if we replace, we got:
P(Z|A) = (0.15)/(0.25) and this is equal to 0.6.
For Part B, we have: P(A|Z)=P(Z and A)/P(Z)
P(A|Z) = (0.15)/(0.73) and this is equal to 0.205.
Solution:
Given:

when a = 4, substitute for a in the expression;

Therefore, if (a = 4), then

Hence, the answer is 16.
Answer: 3.5 integers can be in decimals too. and any number counts as an integer except for 0
Answer:
1/27
Step-by-step explanation:
There are 9 numbers between 0 and 8. 3 of them are less than 3 (0, 1, and 2), and 1 of them is 6.
The probability is therefore (3/9) (1/9) = 1/27.