If a cube-shaped cell is 3 units tall by 3 units wide and 3 units long, what is the cell's surface-area-to volume ratio?
1 answer:
The cube has 6 sides, each a square with dimensions 3 by 3,
the area of any of these squares is 3*3=9 square units.
The total area of the cube is 6*9 square units=54 square units
The volume of a cube with side length a is given by :
, thus the volume of the cube-shaped cell is 3*3*3=27 cube units.
(surface area):(volume)=54:27 = 2:1 =2
Answer:
the ratio of the numerical values is 2
(their ratio including units is 2/unit
the area of any of these squares is 3*3=9 square units.
The total area of the cube is 6*9 square units=54 square units
The volume of a cube with side length a is given by :
(surface area):(volume)=54:27 = 2:1 =2
Answer:
the ratio of the numerical values is 2
(their ratio including units is 2/unit
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ANSWER
EXPLANATION
The given function is
We rewrite this function to obtain,
We now compare this function to
We have
This implies that,
The vertex is (2,-11).
The focus is