If a cube-shaped cell is 3 units tall by 3 units wide and 3 units long, what is the cell's surface-area-to volume ratio?

1 answer:

7 0

The cube has 6 sides, each a square with dimensions 3 by 3,

the area of any of these squares is 3*3=9 square units.

The total area of the cube is 6*9 square units=54 square units

The volume of a cube with side length a is given by : $\displaystyle{ V_{cube}=a^3$ , thus the volume of the cube-shaped cell is 3*3*3=27 cube units.

(surface area):(volume)=54:27 = 2:1 =2

Answer:

the ratio of the numerical values is 2

(their ratio including units is 2/unit

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