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guajiro [1.7K]
3 years ago
11

If a cube-shaped cell is 3 units tall by 3 units wide and 3 units long, what is the cell's surface-area-to volume ratio?

Mathematics
1 answer:
bulgar [2K]3 years ago
7 0
The cube has 6 sides, each a square with dimensions 3 by 3, 

the area of any of these squares is 3*3=9 square units.

The total area of the cube is 6*9 square units=54 square units


The volume of a cube with side length a is given by : \displaystyle{ V_{cube}=a^3, thus the volume of the cube-shaped cell is 3*3*3=27 cube units.


(surface area):(volume)=54:27 = 2:1 =2

Answer: 

the ratio of the numerical values is 2

(their ratio including units is 2/unit 
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\large\text{Hey there!}


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