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guajiro [1.7K]
3 years ago
11

If a cube-shaped cell is 3 units tall by 3 units wide and 3 units long, what is the cell's surface-area-to volume ratio?

Mathematics
1 answer:
bulgar [2K]3 years ago
7 0
The cube has 6 sides, each a square with dimensions 3 by 3, 

the area of any of these squares is 3*3=9 square units.

The total area of the cube is 6*9 square units=54 square units


The volume of a cube with side length a is given by : \displaystyle{ V_{cube}=a^3, thus the volume of the cube-shaped cell is 3*3*3=27 cube units.


(surface area):(volume)=54:27 = 2:1 =2

Answer: 

the ratio of the numerical values is 2

(their ratio including units is 2/unit 
You might be interested in
Multiply.
Ilya [14]

Answer:

Use synthetic division to determine whether x – 4 is a factor of:

–2x5 + 6x4 + 10x3 – 6x2 – 9x + 4

For x – 4 to be a factor, you must have x = 4 as a zero. Using this information, I'll do the synthetic division with x = 4 as the test zero on the left:

completed division

Since the remainder is zero, then x = 4 is indeed a zero of –2x5 + 6x4 + 10x3 – 6x2 – 9x + 4, so:

Yes, x – 4 is a factor of –2x5 + 6x4 + 10x3 – 6x2 – 9x + 4

Find all the factors of 15x4 + x3 – 52x2 + 20x + 16 by using synthetic division.

Remember that, if x = a is a zero, then x – a is a factor. So use the Rational Roots Test (and maybe a quick graph) to find a good value to test for a zero (x-intercept). I'll try x = 1:

completed division

This division gives a zero remainder, so x = 1 must be a zero, which means that  x – 1 is a factor. Since I divided a linear factor (namely, x – 1) out of the original polynomial, then my result has to be a cubic: 15x3 + 16x2 – 36x – 16. So I need to find another zero before I can apply the Quadratic Formula. I'll try x = –2:

completed division

Since I got a zero remainder, then x = –2 is a zero, so x + 2 is a factor. Plus, I'm now down to a quadratic, 15x2 – 14x – 8, which happens to factor as:

(3x – 4)(5x + 2)

Then the fully-factored form of the original polynomial is:

15x4 + x3 – 52x2 + 20x + 16

= (x – 1)(x + 2)(3x – 4)(5x + 2)

Given that  x = -3 + sqrt(11)   is a zero of x4 + 6x3 – 7x2 – 30x + 10, fully solve the

equation x4 + 6x3 – 7x2 – 30x + 10 = 0.

Since they have given me one of the zeroes, I'll use synthetic division to divide it out:

completed division

(You will probably want to use scratch paper for the computations required when manipulating the radical root.) Copyright © Elizabeth Stapel 2002-2011 All Rights Reserved

Since you only get these square-root answers by using the Quadratic Formula, and since the square-root part of the Formula is preceded by a "plus-minus" sign, then these square-root answers must always come in pairs. Thus, if x = -3 + sqrt(11) is a root, then so also must x = -3 - sqrt(11) be a root. So my next step is to divide by x = -3 - sqrt(11):

completed division

I had started with a fourth-power polynomial. After the first division, I was left with a cubic (with very nasty coefficients!). After the second division, I'm now down to a quadratic (x2 + 0x – 5, or just x2 – 5), which I know how to solve:

x = +/- sqrt(5)

Then the full solution is:

x = -3 +/- sqrt(11), +/- sqrt(5)

If you have studied complex numbers, then you may see a problem of the following type.

Given that 2 – i is a zero of x5 – 6x4 + 11x3 – x2 – 14x + 5, fully solve the

equation  x5 – 6x4 + 11x3 – x2 – 14x + 5 = 0.

They have given us a zero, so I'll use synthetic division and divide out 2 – i:

completed division

(You will probably want to use scratch paper for the computations required when doing complex division.)

Recall that, to arrive at a zero of 2 – i, they must have used the Quadratic Formula, which always spits out complex answers in pairs. That is, you get the imaginary part (the part with the "i") from having a negative inside the "plus or minus square-root of" part of the Formula. This means that, since 2 – i is a zero, then 2 + i must also be a zero.  So I'll divide by 2 + i:

completed division

This leaves me with a cubic, so I'll need to find another zero on my own. (That is, I can't apply the Quadratic Formula yet.) I can use the Rational Roots Test to help find potential zeroes, and a quick graph of x3 – 2x2 – 2x + 1 can help. I will try x = –1:

completed division

Now I'm down to a quadratic (x2 – 3x + 1, which happens not to factor), so I'll apply the Quadratic Formula to get:

x = (3 +/- sqrt(5))/2

Then all the zeroes of x5 – 6x4 + 11x3 – x2 – 14x + 5 are given by:

x = 2 - i, 2 + i, (3 - sqrt(5))/2, (3 + sqrt(5))/2, -1

Step-by-step explanation:

3 0
3 years ago
What is the relationship between the graphs of y = 2x and y = 2-x?
melomori [17]

Answer:

The relationship between the graphs is the intersection point at (0.667,1.333)

Step-by-step explanation:

we have

y=2x ----> equation A

The slope of the line A is equal to m=2

The line passes through the origin

y=2-x ----> equation B

The slope of the line B is m=-1

The x-intercept is the point (2,0)

The y-intercept is the point (0,2)

Line A and Line B are not parallel (the slopes are not equal)

Line A and Line B are not perpendicular (the product of their slopes is not equal to -1)

so

The relationship between Line A and Line B is the intersection point both graphs

using a graphing tool

The intersection point is (0.667,1.333)

see the attached figure

The intersection point is a common point , therefore belongs to both lines

8 0
3 years ago
X^2+3x+2=0 solve by factoring
goldfiish [28.3K]

Answer: x=-1,-2

Step-by-step explanation:

X^2+3x+2=0

(x+1)(x+2)=0

x=-1,-2

4 0
3 years ago
Find the y-intercept of the line on the graph. ​
jeka57 [31]
It looks like it is -1 chief
3 0
3 years ago
Axis of symmetry for f(x) = -2x2 + 20x -42
Ksenya-84 [330]
For the function f(x)=2x^2 +20x-42

We can use the formula for the axis of symetry, which is x= \frac{-b}{2a}

With the values substituted, we get...

\frac{-20}{2(-2)} =5

Therefore the axis of symmetry is x=5 
8 0
3 years ago
Read 2 more answers
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