Melanie:
Amount after 5 years = 4000(1 + 0.04)⁵ = $4867

Gina:
Amount after 5 years = 4000 + 5(0.045 x 4000) = $4900

Answer: Gina has the greater balance and her balance is $4900.

4 0

3 years ago

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A professor wants to award prizes for 1st, 2nd, 3rd, 4th and 5th in the class of 30. In how many ways can the prizes be awarded

aniked [119]

Answer:

$Selection = 17100720\ ways$

Step-by-step explanation:

Given

$Students = 30$

$Positions = 5$ i.e. first to fifth

Required

Determine number of selection

1st position = Any of the 30 students

2nd position = Any of the 29 students

3rd position = Any of the 28 students

4th position = Any of the 27 students

5th position = Any of the 26 students

Number of selection is then calculated as:

$Selection = 30 * 29 * 28 * 27 * 26$

$Selection = 17100720\ ways$

8 0

3 years ago

Solve the simultaneous equations by substitution 4x+3y=-2 3y=4-x

stiv31 [10]

Answer: x=-2 y=2

Step-by-step explanation:

I decided that isolating the y value of the second equation is the best way to start solving.

I divide 3 from both sides to get y= (4-x)/3. With this, I can substitute into the first equation. 4x+3(4-x)/3)=-2.

The multiplying the 3 by the denominator three cancels each other out to make:

4x+4-x=-2.

We subtract 4 on both sides and then subtract x from 4x.

We end up with 3x=-6. Then, we divide both sides by 3.

x=-2.

Now we substitute this into the second equation to solve.

3y=4-(-2)

This becomes 3y=4+2 which is 3y=6

We divide both sides by 3 to get y=2

We end up with x=-2 and y=2.

I hope you learned something :)

4 0

3 years ago

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Triangle ABC has vertices A(-2, 3), B(0, 3), and C(-1,-1). Find the coordinates of the image after a reflection over the

motikmotik

Given:

Given that the triangle ABC has vertices A(-2,3), B(0,3) and C(-1,-1).

We need to determine the coordinates of the image after a reflection over the x - axis.

Let A'B'C' denote the coordinates of the triangle after a reflection over the x - axis.

Coordinates of the point A':

The general rule to reflect the coordinate across the x - axis is given by

$(x,y)\rightarrow (x,-y)$

Substituting the point A(-2,3), we get;

$(-2,3)\rightarrow (-2,-3)$

Thus, the coordinates of the point A' is (-2,-3)

Coordinates of the point B':

The general rule to reflect the coordinate across the x - axis is given by

$(x,y)\rightarrow (x,-y)$

Substituting the point B(0,3), we get;

$(0,3)\rightarrow (0,-3)$

Thus, the coordinates of the point B' is (0,-3)

Coordinates of the point C':

The general rule to reflect the coordinate across the x - axis is given by

$(x,y)\rightarrow (x,-y)$

Substituting the point C(-1,-1), we get;

$(-1,-1)\rightarrow (-1,1)$

Thus, the coordinates of the point C' is (-1,1)

Hence, the coordinates of the image after a reflection over the x - axis is A'(-2,-3), B(0,-3) and C(-1,1)

8 0

3 years ago