Question Completion with Options:
a. increasing the size of your cohorts.
b. increasing the diversity of your cohorts.
c. increasing the size of your affected cohort.
d. increasing the diversity of your affected cohort.
Answer:
All of the following modifications to the study are likely to allow identification of new variants associated with the disease, EXCEPT
a. increasing the size of your cohorts.
Explanation:
Option A is chosen because increasing the size of the cohorts will be equally divided between the affected and unaffected cohorts since the study discovered that these two classes are roughly the same size. Therefore, new variants of the disease may not likely be identified and isolated unless the other modification options are followed instead of Option A.
Answer:
<h2>
Haploid=13</h2><h2>
triploid=39 </h2><h2>
tetraploid=52</h2><h2>
trisomic=14 </h2><h2>
monosomic=12</h2>
Explanation:
Given;
A species with a diploid number of 26, so 26= 2n ( a diploid cell),
so in haploid condition, chromosome number becomes half (13 in this case). triplod is when 2n + n, and 2n +2n ( tetploid). Trisomy and monosomy is the addition or deletion of a sinlge chromosome of a sinlge set .
Haploid=13, one chromosome from each pair of chromosome set,
triploid=39 (13× 3); diploid+ n( 3n)
tetraploid=52 (13× 4) 4n
trisomic=14 (13+1) ; n+1
monosomic=12 (13-1); n-1
Answer:
Eukaryote and Prokaryote
Eukaryotes have a nucleus and prokaryotes don't
Answer:
B) Post-zygotic factors prevented successful reproduction.
Explanation:
Postzygotic factors may influence the formation of the fertile offspring.
The postzygotic barriers basically involves the formation of the hybrid organisms which do not survive past the embryonic stages i-e hybrid inviability / the hybrid creation that is unable to form the offspring i-e sterile.
So , in the given scenario option B )Post-zygotic factors prevented successful reproduction is the right answer .
A lot of cells are needed to create a living organism. infinity cells are needed
