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katrin [286]
3 years ago
4

The break statement is required in the default case of a switch selection to the exit structure properly. True/False

Computers and Technology
1 answer:
Oksi-84 [34.3K]3 years ago
4 0

Answer: True

Explanation: Break statements are the statements is for the termination of the loop .It is considered as the statements that control the loop. For the default case ,default method is used in the switch selection statements.

The Switch selection statement,due to the working of the break statement will exit or terminate. Thus, the statement given in the question is correct.

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Write a program that: Takes the list lotsOfNumbers and uses a loop to find the sum of all of the odd numbers in the list (hint:
Alika [10]

Answer:

Following are the code to this question:

#include <iostream>//defining header file

using namespace std;

int main()//defining main method

{

int x[]={2,3,4,6,7,8,9,1,11,12};//defining 1-D array and assign value

int i,sum=0;//defining integer variable

for(i=0;i<10;i++)//defining loop for count value

{

   if(x[i]%2==1)//defining if block to check odd value

   {

       sum=sum+x[i];//add value in sum variable

   }

}

cout<<sum;//print sum

return 0;

}

Output:

31

Explanation:

In the above-given program, an integer array "x" is declared that holds some integer values, and in the next line two integer variable "i and sum" is defined which is used to calculate the value.

In the next line, a for loop is declared, that counts all array value, and it uses the if block to check the odd value and add all the value into the sum variable.

5 0
3 years ago
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