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Julli [10]
3 years ago
14

Who is responsible for the actions of autonomous systems? (please help me :C)

Computers and Technology
2 answers:
Oksanka [162]3 years ago
8 0

The responsibility for failures was deflected away from the automated parts of the system (and the humans, such as engineers, whose control is mediated through this automation) and placed on the immediate human operators, who possessed only limited knowledge and control.

blagie [28]3 years ago
3 0
Ohio university college
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Focusing on the general characteristics of a problem or object, while ignoring the details, is a technique called
Taya2010 [7]

Answer:

Abstraction

Explanation:

In computer science, abstraction has a similar definition. It is a simplified version of something technical, such as a function or an object in a program. The goal of "abstracting" data is to reduce complexity by removing unnecessary information. At some level, we all think of computers in abstract terms.

5 0
2 years ago
The purpose of this assignment is to determine a set of test cases knowing only the function’s specifications, reported hereaf
Nesterboy [21]

Answer:

The program is written using PYTHON SCRIPT below;

N=int(input(" Enter number of Rows you want:"))

M=[] # this for storing the matrix

for i in range(N):

l=list(map(int,input("Enter the "+str(i+1)+" Row :").split()))

M.append(l)

print("The 2D Matrix is:\n")

for i in range(N):

print(end="\t")

print(M[i])

W=[] # to store the first non zero elemnt index

T=[] # to store that value is positive or negative

L=len(M[0])

for i in range(N):

for j in range(L):

if (M[i][j]==0):

continue

else:

W.append(j) # If the value is non zero append that postion to position list(W)

if(M[i][j]>0): #For checking it is positive or negative

T.append(+1)

else:

T.append(-1)

break

print()

print("The first Non Zero element List [W] : ",end="")

print(W)

print("Positive or Negative List [T] : ",end="")

print(T)

Explanation:

In order for the program to determine a set of test cases it takes in input of 2D matrix in an N numbet of rows.

It goes ahead to program and find the column index of the first non-zero value for each row in the matrix A, and also determines if that non-zero value is positive or negative. The If - Else conditions are met accordingly in running the program.

5 0
3 years ago
To save your new document or presentation, click the Start Button
Vika [28.1K]
No you would click save or save as
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3 years ago
Which option in a Task element within Outlook indicates that the task is scheduled and will be completed on a later
joja [24]
I think it’s in progress
5 0
2 years ago
Read 2 more answers
Greedy Algorithm Design
Alik [6]

Answer:

The algorithm is as follows:

1. Start

2. Get the number of items (n)

3. Get the current price of the n items (a1, a2..... an)

4. Get the possible hiked price of the n items (b1, b2..... bn)

5. Calculate the difference between the current and hiked prices for each item i.e. d_i = b_i - a_i

6. Sort the differences in descending order (i.e. from the greatest to the least)

7. Buy items in this order of difference

8. Stop

Explanation:

The algorithm is self-explanatory; however, what it does is that:

It takes a list of the current price of items (say list a)

E.g: a = [100, 150, 160]

Then take a list of the hiked price of the items (say list b)

E.g: b = [110, 180, 165]

Next, it calculates the difference (d) between corresponding prices d_i = b_i - a_i

d = [(110 - 100),(180-150),(165-160)]

d = [10,30,5]

Sort the difference from greatest to lowest (as the difference is sorted, lists a and b are also sorted)

d = [30,10,5]

a = [150, 100, 160]

b = [180, 110, 165]

If there is no hike up to item k, the couple would have saved (i = 1 to d[k-1])

Assume k = 3

The couple would have saved for 2 item

Savings = d[1] + d[2]

Savings = 30 +10

Savings = 40

The saved amount will then be added to the kth item in list a i.e. a[k](in this case k = 3) in order to buy b[k]

Using the assumed value of k

a[k] = a[3]

a[3] = 160

b[3] = 165

Add the saved amount (40) to a[3]

New\ Amount = 40 + 160

New\ Amount = 200

This new amount can then be used to buy b[3] i.e. 165, then they save the change for subsequent items

8 0
3 years ago
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