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Rufina [12.5K]
3 years ago
5

Write a program that: Takes the list lotsOfNumbers and uses a loop to find the sum of all of the odd numbers in the list (hint:

use Mod). Displays the sum.
Computers and Technology
1 answer:
Alika [10]3 years ago
5 0

Answer:

Following are the code to this question:

#include <iostream>//defining header file

using namespace std;

int main()//defining main method

{

int x[]={2,3,4,6,7,8,9,1,11,12};//defining 1-D array and assign value

int i,sum=0;//defining integer variable

for(i=0;i<10;i++)//defining loop for count value

{

   if(x[i]%2==1)//defining if block to check odd value

   {

       sum=sum+x[i];//add value in sum variable

   }

}

cout<<sum;//print sum

return 0;

}

Output:

31

Explanation:

In the above-given program, an integer array "x" is declared that holds some integer values, and in the next line two integer variable "i and sum" is defined which is used to calculate the value.

In the next line, a for loop is declared, that counts all array value, and it uses the if block to check the odd value and add all the value into the sum variable.

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Answer:

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Explanation:

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What's the component of the hardware?​
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7 0
2 years ago
Read 2 more answers
Flowgorithm, Design a program that prompts the user to enter a number within the range of 1 through 10. The program should displ
kherson [118]

Answer:

Step by step code along with explanation and output is given below

Explanation:

We can solve this problem using if elif else approach

def main():

# prompts the user to enter an integer from 1 to 10

 num = int (input('Enter a number in the range of 1 to 10:\n'))

# using the if elif print out the roman numeral from 1 to 10

 if num == 1:

   print ('Roman Numeral for 1 is I')

 elif num == 2:

   print ('Roman Numeral for 2 is II')

 elif num == 3:

   print ('Roman Numeral for 3 is III')

 elif num == 4:

   print ('Roman Numeral for 4 is IV')

 elif num == 5:

   print ('Roman Numeral for 5 is V')

 elif num == 6:

   print ('Roman Numeral for 6 is VI')

 elif num == 7:

   print ('Roman Numeral for 7 is VII')

 elif num == 8:

   print ('Roman Numeral for 8 is VIII')

 elif num == 9:

   print ('Roman Numeral for 9 is IX')

 elif num == 10:

   print ('Roman Numeral for 10 is X')

# using the else print out error message whenever user enters any other number not listed above

 else:

   print ('Error! Wrong Input')

# call the main function

main()

Output:

Enter a number in the range of 1 to 10:

6

Roman Numeral for 6 is VI

Enter a number in the range of 1 to 10:

15

Error! Wrong Input

6 0
3 years ago
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