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3 years ago

Can someone help me with this question?

Mathematics

1 answer:

belka [17]3 years ago

4 0

Option 3 (1/4 x 60) since 59 is close to 60 and 25% can be rewritten as 1/4

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There are 5 students in class. each will be assigned a grade of a, b or

antiseptic1488 [7]

There could be five in each class.

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3 years ago

(a) A house costs 36% more today than when it

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1 year ago

Read 2 more answers

4 Solve the system to find the y-value of the

ser-zykov [4K]

Answer: B

Step-by-step explanation:

7(-2) - 4(1) = -18

-14 - 4 = -18

-18 = -18

TRUE

(-2) + 12(1) = 10

-2 + 12 = 10

10 = 10

TRUE

3 0

2 years ago

Line segment NY has endpoints N(-11, 5) and Y(3,-3).

777dan777 [17]

Given:

Line segment NY has endpoints N(-11, 5) and Y(3,-3).

To find:

The equation of the perpendicular bisector of NY.

Solution:

Midpoint point of NY is

$Midpoint=\left(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\right)$

$Midpoint=\left(\dfrac{-11+3}{2},\dfrac{5-3}{2}\right)$

$Midpoint=\left(\dfrac{-8}{2},\dfrac{2}{2}\right)$

$Midpoint=\left(-4,1\right)$

Slope of lines NY is

$m=\dfrac{y_2-y_1}{x_2-x_1}$

$m=\dfrac{-3-5}{3-(-11)}$

$m=\dfrac{-8}{14}$

$m=\dfrac{-4}{7}$

Product of slopes of two perpendicular lines is -1. So,

$m_1\times \dfrac{-4}{7}=-1$

$m_1=\dfrac{7}{4}$

The perpendicular bisector of NY passes through (-4,1) with slope $\dfrac{7}{4}$ . So, the equation of perpendicular bisector of NY is

$y-y_1=m_1(x-x_1)$

$y-1=\dfrac{7}{4}(x-(-4))$

$y-1=\dfrac{7}{4}(x+4)$

$y-1=\dfrac{7}{4}x+7$

Add 1 on both sides.

$y=\dfrac{7}{4}x+8$

Therefore, the equation of perpendicular bisector of NY is $y=\dfrac{7}{4}x+8$ .

6 0

3 years ago

Please help ill give BRAINLIEST

S_A_V [24]

Answer:

B and D

Step-by-step explanation:

6 0

2 years ago