Mark worked 5 2/3, 9 1/3, 8 3/5, 9 2/5, and 9 hours during the week. If he earns $6.55 per hour, how much did he earn before ded
2 answers:
Answer:
Option B is right
Step-by-step explanation:
Given that pay per hour is 6.55
As per practice, above 40 hours per week is treated as over time and paid as 1.5 times regular pay per hour
Total hours Mark worked during the week
= Sum of 5 2/3, 9 1/3, 8 3/5, 9 2/5, and 9 hours
Let us make these as improper fractions then we can take lcd and add
Hence pay would be for 40 hours regular rate and 2 hours overtime rate
Total pay = 40(6.55)+2(6.55)(1.5)
=262+19.65
=281.65
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