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Anika [276]
3 years ago
5

Mark worked 5 2/3, 9 1/3, 8 3/5, 9 2/5, and 9 hours during the week. If he earns $6.55 per hour, how much did he earn before ded

uctions? (This may involve overtime.) $312.99 $281.65 $201.84 $288.12
Mathematics
2 answers:
serious [3.7K]3 years ago
8 0
Thank you for posting your question here. Below is the solution:

ark worked 5 2/3 + 9 1/3 = 15 hours. 8 3/5 + 9 2/5 = 18 hours + 9 hours. 
<span>15 + 18 + 9 = 42 hours worked @ $6.55 per hour </span>
<span>40 hours regular pay and 2 hours overtime. </span>
<span>Over time is 1 1/2 X $6.55 = $9.83 per hour X 2 hours overtime worked = $19.65 in over time . </span>
<span>40 hours @ $6.55 = $262.00 + $19.65 = $281.65.Gross pay </span>

<span>Chris. </span>
<span>5 1/2 + 9 1/2 = 15 hours </span>
<span>8 4/5 + 5 1/5 = 14 hours </span>
<span>14 + 15 = 29 hours worked. @ $9.65 per hour = $279.85 Gross pay </span>
Softa [21]3 years ago
6 0

Answer:

Option B is right

Step-by-step explanation:

Given that pay per hour is 6.55

As per practice, above 40 hours per week is treated as over time and paid as 1.5 times regular pay per hour

Total hours Mark worked during the week

= Sum of 5 2/3, 9 1/3, 8 3/5, 9 2/5, and 9 hours

Let us make these as improper fractions then we can take lcd and add

\frac{17}{3} +\frac{28}{3} +\frac{43}{5} +\frac{47}{5} +\frac{9}{1}\\=\frac{85+140+129+141+135}{15} \\=\frac{630}{15} \\=42

Hence pay would be for 40 hours regular rate and 2 hours overtime rate

Total pay = 40(6.55)+2(6.55)(1.5)

=262+19.65

=281.65

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