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3 years ago

Enter the trigonometric equation you would use to solve for x in the following right triangle. Do not solve the equation.

Mathematics

1 answer:

USPshnik [31]3 years ago

6 0

Answer:

x = sine 70° / 8

Step-by-step explanation:

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Idk this pls help don’t understand.

lawyer [7]

Answer: 60, but I got other answers to but 60 was my first.

sorry if wrong.

Step-by-step explanation:

7 0

3 years ago

Plzzzzz help Me I'm not smart

MAVERICK [17]

Answer:

(3X8) - 4 + 2 - 12

Step-by-step explanation:

Following the order of operations solve:

(24) - 4 + 2 - 12

20 + 2 - 12

22 - 12

Don't feel bad, this is an odd question and the parenthesis do not seem to be required. Following the order of operations would result in the same answer anyway...

Odd.

3 0

3 years ago

Read 2 more answers

I have a question for you

egoroff_w [7]

Answer:

10 5/6

Step-by-step explanation:

First we have to make 2 1/6 into an improper fraction. This can be rewritten as 13/6. Now, we can multiply 13 by 5 and get 65/6. If we re-convert this into a mixed number, 6 goes into 65 10 times with a remainder of 5, so the final answer is 10 5/6.

4 0

3 years ago

Which of the following is the result of the equation below after completing the square and factoring? x^2+3x+8=6

Inessa05 [86]

Answer:

Step-by-step explanation:

6 0

3 years ago

A teacher was interested in knowing the amount of physical activity that his students were engaged in daily. He randomly sampled

klasskru [66]

Answer:

The standard error of the mean is 4.5.

Step-by-step explanation:

As we don't know the standard deviation of the population, we can estimate the standard error of the mean from the standard deviation of the sample as:

$\sigma_{\bar{x}}\approx\frac{s}{\sqrt{n}}$

The sample is [30mins, 40 mins, 60 mins, 80 mins, 20 mins, 85 mins]. The size of the sample is n=6.

The mean of the sample is:

$\bar{x}=\frac{1}n} \sum x_i =\frac{30+40+60+80+20+85}{6}=52.5$

The standard deviation of the sample is calculated as:

$s=\sqrt{\frac{1}{n-1}\sum (x_i-\bar x)^2} \\\\ s=\sqrt{\frac{1}{5}\cdot ((30-52.5)^2+(40-52.5)^2+(60-52.5)^2+(80-52.5)^2+(20-52.5)^2+(85-52.5)^2}\\\\s=\sqrt{\frac{1}{5} *3587.5}=\sqrt{717.5}=26.8$

Then, we can calculate the standard error of the mean as:

$\sigma_{\bar{x}}\approx\frac{s}{\sqrt{n}}=\frac{26.8}{6}= 4.5$

6 0

3 years ago