Ask question

Ask question

All categories

3 years ago

13

to graph y=2/3x+4 Emaan plots one point at 0,4 and a second point 2 units right and 3 units up at 2,7 he then draws a line throu

gh 0,4 and 2,7 what error did emaan make

1 answer:

3241004551 [841]3 years ago

8 0

3 units up at 2,7 he then draws a line through 0,4 and 2,7

You might be interested in

The smithsons are going to Dallas,TX on vacation. They have traveled 1/3 of the total distance. If they traveled 126 miles,how f

Ronch [10]

If 1/3 is 126 miles, then the total distance will be 3 times as much. So just doing:

126 * 3 = 378 miles.

Gives us the answer 378 miles. This is an intro to inverse functions which will come later.

6 0

3 years ago

Which pairs of polygons are similar?<br> Select each correct answer

kotegsom [21]

Answer:

Left column:

1 & 2

right column:

1 & 2

pls mark me brainliest!!!

6 0

3 years ago

Trish and Alex are comparing the population of different cities in texas Alex says the population of a city is always an integer

siniylev [52]

Yes - you can't have half a person.

8 0

3 years ago

The number 0.35 is a(n) __________ number because __________.

worty [1.4K]

Rational number because /An irrational number has endless non-repeating digits to the right of the decimal point.

8 0

2 years ago

Read 2 more answers

When an amount of heat Q (in kcal) is added to a unit mass (kg) of a

lisov135 [29]

Answer:

The change in temperature per minute for the sample, dT/dt is 71. $\overline {6}$ °C/min

Step-by-step explanation:

The given parameters of the question are;

The specific heat capacity for glass, dQ/dT = 0.18 (kcal/°C)

The heat transfer rate for 1 kg of glass at 20.0 °C, dQ/dt = 12.9 kcal/min

Given that both dQ/dT and dQ/dt are known, we have;

$\dfrac{dQ}{dT} = 0.18 \, (kcal/ ^{\circ} C)$

$\dfrac{dQ}{dt} = 12.9 \, (kcal/ min)$

Therefore, we get;

$\dfrac{\dfrac{dQ}{dt} }{\dfrac{dQ}{dT} } = {\dfrac{dQ}{dt} } \times \dfrac{dT}{dQ} = \dfrac{dT}{dt}$

$\dfrac{dT}{dt} = \dfrac{\dfrac{dQ}{dt} }{\dfrac{dQ}{dT} } = \dfrac{12.9 \, kcal / min }{0.18 \, kcal/ ^{\circ} C } = 71.\overline 6 \, ^{\circ } C/min$

For the sample, we have the change in temperature per minute, dT/dt, presented as follows;

$\dfrac{dT}{dt} = 71.\overline 6 \, ^{\circ } C/min$

8 0

2 years ago