Given:
U be the set of all books, N the set of all novels, and H be the set of all hardcover books.
To find:
The description for the sets 
and 
in words.
Solution:
We have,
U = The set of all books
N = The set of all novels
H = The set of all hardcover books.
We know that means common elements of set N and set H.
Therefore, is set of all books that are both novels and hardcover books.
We know that is the set of elements of universal set except the elements of set H.
Therefore, is the set of all books that are not hardcover books.
Add the ratios together and divide them by 132. then times the number by the answer you get.
3+3+5=11
132÷11=12
12×3=36
12×3=36
12×5=60
so: 36:36:60
Answer:
C
Step-by-step explanation:
B is an endpoint of this line, and C continues forever (illustrated by the arrow)
Answer:
D.pi
Step-by-step explanation:
Because it’s pi
For this case we define the following variable:
- <em>x: number of stamps
</em>
We now write the equation that models the problem:
From here, we clear the value of x.
We have then:
Answer:
The number of stamps he has is:
