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Dmitrij [34]
3 years ago
5

( − 6 u 9 − 14 u 3 ) + ( − 13 u + 2 u 9 )

Mathematics
2 answers:
sergeinik [125]3 years ago
8 0
Answer is -91


Dondt know explanation
OverLord2011 [107]3 years ago
5 0

Answer:=−91u

Step-by-step explanation:

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5(<br> 5X<br> –<br> 10)<br> =<br> 15 solve it ​
olga55 [171]
5(5x-10)=15
5x-10=3
5x=10+3
5x=13
Divide both sides by 5-5 and 5 cancel out to leave you with x 13/5 =2.6
X=2.6
5 0
3 years ago
-6/5k=12 what is k? please explain
pentagon [3]

Answer:.......

Step-by-step explanation:

3 0
4 years ago
Read 2 more answers
Find the distance between the points (3, 7) and (2, 6)​
solong [7]

Answer:

1.414214

Step-by-step explanation:

I think this is right lol.

6 0
3 years ago
How would you solve for these
statuscvo [17]

Answer: 1) x> -21

2) x is less than or equal to -21

3) x is less than or equal to 16

4) x less than or equal to 3/4

8 0
3 years ago
An object is propelled upward from the top of a 300 foot building. The path that the object takes as it falls to the ground can
serg [7]

Answer:

As per the statement:

The path that the object takes as it falls to the ground can be modeled by:

h =-16t^2 + 80t + 300

where

h is the height of the objects and

t is the time (in seconds)

At t = 0 , h = 300 ft

When the objects hit the ground, h = 0

then;

-16t^2+80t+300=0

For a quadratic equation: ax^2+bx+c=0         ......[1]

the solution for the equation is given by:

x = \frac{-b\pm \sqrt{b^2-4ac}}{2a}

On comparing the given equation with [1] we have;  

a = -16 ,b = 80 and c = 300

then;

t= \frac{-80\pm \sqrt{(80)^2-4(-16)(300)}}{2(-16)}

t= \frac{-80\pm \sqrt{6400+19200}}{-32}

t= \frac{-80\pm \sqrt{25600}}{-32}  

Simplify:

t = -\frac{5}{2} = -2.5 sec and t = \frac{15}{2} = 7.5 sec

Time can't be in negative;

therefore, the time it took the object to hit the ground is 7.5 sec

8 0
4 years ago
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