Найдите корни уранения |t|:6=4
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Answer would be B. Sorry if my handwriting is messy or if I didn’t explain enough
The coordinates of point F are (15/4 , -5/2)
- The coordinates of point G = (-3/4 , -3)
From the image attached:
AB divided into 4 similar parts, hence
- E is the mid-point of AB
- D is the mid-point of AE
- F is the mid-point of EB
Note that the rule of the mid-point states that:
When M (x , y) is the mid-point of the segment of AB, where A (x1 , y1) and B (x2 , y2), Then x = (x1 + x2)/2 and that of y = (y1 + y2)/2
Then lets solve for points E, F, D
Since A (-3 , -1) and B (6 , -3),
E is the mid-point of AB
Then E =[(-3 + 6)/2, (-1 + -3)/2]
= (3/2 , -2)
Since F is the mid-point of EB,
E (3/2 , -2) , B (6 , -3)
Then F = [(3/2 + 6)/2 , (-2 + -3)/2]
= (15/4 , -5/2)
Since D is the mid-point of AE, A (-3 , -1), E (3/2 , -2)
Then D = [(-3 + 3/2)/2 , (-1 + -2)/2]
= (-3/4 , -3/2)
Note also that:
BC is said to be an horizontal segment due to the fact that B and C have similar y - coordinate and G can be found on BC.
Since the y-coordinate of G is similar to y-coordinate of B and C
Then y-coordinate of G is = -3
Since DG ⊥ BC
Then DG = vertical segment
So G has similar x-coordinate of D
Then The x-coordinate of G = -3/4
The G = (-3/4 , -3)
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The results of the survey are shown in the table.
It's required to calculate the following probabilities:
a) A customer is neutral
The row labeled as 'Neutral' has a total of 79 customers out of 367 in total.
The required probability is:
b) A customer is a walk-in
The first column labeled as 'Walk-in' has a total of 106 customers out of 367. The required probability is
c) A customer is dissatisfied and a walk-in.
We have to cross the row Dissatisfied with the column Walk-in. The number of customers that have both categories is 22 out of 367.
The required probability is:
d) A customer is very satisfied given he saw a TV ad.
This is a conditional probability, where the total is 111 because is the given condition. The customers that have both characteristics are 33, thus the required probability is:
e) A customer is satisfied or referred.
Total satisfied = 139
Total referred = 150
With both features = 62
Total customers with one or both features: 139 + 150 - 62 = 227
We have to subtract the common feature because it was counted twice.
The required probability is: