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3 years ago

10

How do you factor out 4v(squared) - 16v + 7?

1 answer:

Salsk061 [2.6K]3 years ago

7 0

It is a square trinomial:
4v^2 - 16v + 7 = 0
lets multiply and divide all by 4, the square term coefficient:
(16v^2 - 16(4)v + 28)(1/4) = 0
(4v - 14)(4v - 2)<span>(1/4) = 0
</span>factor 1/4
(4v - 14)(4v - 2)(1/2)<span>(1/2)</span> = 0
and divide each:
(2v - 7)(2v - 1) = 0

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The equations which are sums of perfect cubes are as follows;

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<h3>Perfect cubes;</h3>

Perfect cubes are the numbers that are the triple product of the same number.

We have to determine

Which are sums of perfect cubes?

1. The given equation is $\rm 8x^6+27x^9+1$ .

The equation can be written as;

$\rm 8x^6+27x^9+1\\\\2^3(x^2)^3+3^3(x^3)^3+1^3$

All the terms in the expression are can be represented as perfect cubes.

2. The given equation is $\rm 81x^3+16x^6$ .

The equation can be written as;

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In this, all the terms are not perfect cubes, some of them are squares.

3. The given equation is $\rm x^6+x^3$ .

The equation can be written as;

$\rm x^6+x^3\\\\(x^2)^3+x^3$

All the terms in the expression are perfect cubes.

4. The given equation is $\rm 27x^9+x^{12}$ .

The equation can be written as;

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All the terms in the expression are perfect cubes.

5. The given equation is $\rm 9x^3+27x^9$ .

The equation can be written as;

$\rm 9x^3+27x^9\\\\3^2x^3+3^3(x^3)^3$

In this, all the terms are not perfect cubes, some of them are squares too.

To know more about perfect cubes click the link given below.

brainly.com/question/4701925

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Step-by-step explanation:

Two lines intersect and create vertical angles.

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