Short answer: I don't know, but that doesn't mean I can't give you something that you can decide for yourself.
y = 4*2^(2n - 2) is the pattern.
Go for broke. Try n = 4. You should get 256. Let's try it.
y = 4 * 2^(2*4 - 2)
y = 4 * 2^(8 - 2)
y = 4 * 2^6
y = 4 * 64
y = 256 yup it works.
The other end is just as important. Suppose n = 1
Then y = 4 * 2^(2*1 - 2) = 4 * 2^0 = 4*1 = 4 Both work.
If this formula is correct, we can abbreviate it to make your task easier.
y = 4 * 2^(2n - 2)
y = 2^2 * 2^(2n - 2)
y = 2^(2n - 2 + 2)
y = 2^(2n) Now try the two end points again.
n = 4
y = 2^(2*4)
y = 2^8
y = 256
n = 1
y = 2^(2*1)
y = 2^2
y = 4 which again checks.
so y = 2^(2n) I think is an exponential function.
Sorry my explanation is so long.
Answer:
14,590
Step-by-step explanation:
Answer: i think yes
Step-by-step explanation:
9514 1404 393
Answer:
- c = 2
- segments 10, 8, 6 (top down)
Step-by-step explanation:
The sum of top and bottom bases is twice the midsegment.
(c² +6) +(c² +2) = 2(4c)
2c² -8c +8 = 0 . . . . . . . . . subtract 8c
2(c -2)² = 0 . . . . . . . . factor
c = 2 . . . . . . the value that makes the binomial be zero
The value of c is 2; the segment lengths (top-down) are 10, 8, 6.
To tessellate a surface using a regular polygon, the interior angle must be a sub-multiple (i.e. factor) of 360 degrees to cover completely the surface.
For a regular three-sided polygon, the interior angle is (180-360/3)=60 °
Since 6*60=360, so a regular three-sided polygon (equilateral triangle) tessellates.
For a regular four-sided polygon, the interior angle is (180-360/4)=90 °
Since 4*90=360, so a regular four-sided polygon (square) tessellates.
For a regular five-sided polygon, the interior angle is (180-360/5)=108 °
Since 360/108=3.33... (not an integer), so a regular five-sided polygon (pentagon) does NOT tessellate.
For a regular six-sided polygon, the interior angle is (180-360/6)=120 °
Since 3*120=360, so a regular six-sided polygon (hexagon) tessellates.
