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3 years ago

7

Jane made $288 for 18 hours of work. At the same rate, how much would she make for 11 hours of work?

1 answer:

Airida [17]3 years ago

3 0

Answer:

176$

Step-by-step explanation:

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Equation of the parabola in vertex form that passes through (4,-7) and has a vertex of (1,-6)

Alina [70]

$y = -\frac{1}{9}(x - 1)^2 - 6$

Step-by-step explanation:

The vertex form of the equation for a parabola is given by

$y = a(x - h)^2 + k$

where (h, k) are the coordinates of the parabola's vertex. Since the vertex is at (1, -6), we can write the equation as

$y = a(x - 1)^2 - 6$

Also, since the parabola passes through (4, -7), we can use this to find the value for a:

$-7 = a(4 - 1)^2 - 6 \Rightarrow -7 = 9a - 6$

or

$a = -\frac{1}{9}$

Therefore, the equation of the parabola is

$y = -\frac{1}{9}(x - 1)^2 - 6$

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2 years ago

How far does the peguin walk in 45 seconds

lesantik [10]

Answer:

Step-by-step explanation:

He does not walk at all if he's swimming.

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3 years ago

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The sum of two numbers is twice their difference. The larger number is 2 more than twice the smaller

Alexandra [31]

The larger number is 6 and the smaller one is 2.

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3 years ago

Which is the inverse of the function a(d)=5d-3? And use the definition of inverse functions to prove a(d) and a-1(d) are inverse

Drupady [299]

Answer:

$a'(d) = \frac{d}{5} + \frac{3}{5}$

$a(a'(d)) = a'(a(d)) = d$

Step-by-step explanation:

Given

$a(d) = 5d - 3$

Solving (a): Write as inverse function

$a(d) = 5d - 3$

Represent a(d) as y

$y = 5d - 3$

Swap positions of d and y

$d = 5y - 3$

Make y the subject

$5y = d + 3$

$y = \frac{d}{5} + \frac{3}{5}$

Replace y with a'(d)

$a'(d) = \frac{d}{5} + \frac{3}{5}$

Prove that a(d) and a'(d) are inverse functions

$a'(d) = \frac{d}{5} + \frac{3}{5}$ and $a(d) = 5d - 3$

To do this, we prove that:

$a(a'(d)) = a'(a(d)) = d$

Solving for $a(a'(d))$

$a(a'(d)) = a(\frac{d}{5} + \frac{3}{5})$

Substitute $\frac{d}{5} + \frac{3}{5}$ for d in $a(d) = 5d - 3$

$a(a'(d)) = 5(\frac{d}{5} + \frac{3}{5}) - 3$

$a(a'(d)) = \frac{5d}{5} + \frac{15}{5} - 3$

$a(a'(d)) = d + 3 - 3$

$a(a'(d)) = d$

Solving for: $a'(a(d))$

$a'(a(d)) = a'(5d - 3)$

Substitute 5d - 3 for d in $a'(d) = \frac{d}{5} + \frac{3}{5}$

$a'(a(d)) = \frac{5d - 3}{5} + \frac{3}{5}$

Add fractions

$a'(a(d)) = \frac{5d - 3+3}{5}$

$a'(a(d)) = \frac{5d}{5}$

$a'(a(d)) = d$

Hence:

$a(a'(d)) = a'(a(d)) = d$

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3 years ago

Am I the only one whose parents yell their name and when you tell back yes mom they don’t answer?

arsen [322]

No your not the only one

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3 years ago

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