The solution to the problem is as follows:
<span>'(t) = 0 gives:
-24t + 60 = 0
t = 2.5
For this t, the second derivative s"(t) = -24 is negative.
And so, s(t) is maximum for t = 2.5.
Maximum height is:
S = -12(2.5)^2 + 60(2.5) +8 = 233ft
</span>
I hope my answer has come to your help. God bless and have a nice day ahead!
Based on the diagram and the ratio of width and height in it, the width that Mr. Howell should make his table is 48 inches .
<h3>How wide should Mr. Howell's table be?</h3>
The width of the table in the diagram is 12 cm and the height is 6cm.
This means that the ratio of width to height is:
12 : 6
2 : 1
As Mr. Howell wants his table to be 24 inches high, the width of the table would be:
2 : 1
x : 24
Cross-multiply to get:
x = 48 inches
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Answer:
Relative frequencies
First row
0.8125 ,0.1875 ,16
Second row
0.555 ,0.444 ,9
third row
18 , 7 , 25
Step-by-step explanation:
Given data
allowance No allowance total
Chores 13 3 16
<u>No chores 5 4 9</u>
<u>Total 18 7 25</u>
<u><em>Relative frequencies</em></u>
allowance No allowance total
Chores
16
No chores
9
Total <u> 18 7 25</u>